Question

在我的表中，我有日期列，其上有默认值TIMESTAMP。我想每小时计算一次我的记录。我像这样使用了sproc

    SELECT username, 


    COUNT(IF(HOUR(date)=8,1,NULL)  and (IF(docs != null))) AS '8:30  - 9:00', 
    COUNT(IF(HOUR(date)=9,1,NULL)  and (IF(docs != null))) AS '9:00 - 10:00',
    COUNT(IF(HOUR(date)=10,1,NULL) and (IF(docs != null))) AS '10:00 - 11:00',
    COUNT(IF(HOUR(date)=11,1,NULL) and (IF(docs != null))) AS '11:00 - 12:00',
    COUNT(IF(HOUR(date)=12,1,NULL) and (IF(docs != null))) AS '12:00 - 1:00',
    COUNT(IF(HOUR(date)=13,1,NULL) and (IF(docs != null))) AS '1:00 - 2:00',
    COUNT(IF(HOUR(date)=14,1,NULL) and (IF(docs != null))) AS '2:00 - 3:00',
    COUNT(IF(HOUR(date)=15,1,NULL) and (IF(docs != null))) AS '3:00 - 4:00',
    COUNT(IF(HOUR(date)=16,1,NULL) and (IF(docs != null))) AS '4:00 - 5:00',
    COUNT(disblid) 'Total'


FROM claimloans 
group by username;

没有

and (IF(docs != null))

部分我的sproc工作完美。如果行doc值为null，我不想计算行。我怎么能做到这一点？

这是我的工作程序

SELECT username, 

    COUNT(IF(HOUR(date)=8,1,NULL))  AS '8:30  - 9:00', 
    COUNT(IF(HOUR(date)=9,1,NULL))  AS '9:00 - 10:00',
    COUNT(IF(HOUR(date)=10,1,NULL)) AS '10:00 - 11:00',
    COUNT(IF(HOUR(date)=11,1,NULL)) AS '11:00 - 12:00',
    COUNT(IF(HOUR(date)=12,1,NULL)) AS '12:00 - 1:00',
    COUNT(IF(HOUR(date)=13,1,NULL)) AS '1:00 - 2:00',
    COUNT(IF(HOUR(date)=14,1,NULL)) AS '2:00 - 3:00',
    COUNT(IF(HOUR(date)=15,1,NULL)) AS '3:00 - 4:00',
    COUNT(IF(HOUR(date)=16,1,NULL)) AS '4:00 - 5:00',
    COUNT(disblid) 'Total'


FROM claimloans 
group by username;

Answer 1

Nothing is ever equal to null（x = null和x != null都是假的），因此您需要将docs != NULL更改为docs IS NOT NULL。

Answer 2

所以，这个表达式：

COUNT(IF(HOUR(date)=8,1,NULL))

当1的小时数为8时，

计算date这是一个硬编码的非空表达式。如果将1替换为doc：

COUNT(IF(HOUR(date)=8,doc,NULL))

该函数还将根据doc的内容进行计数。也就是说，它不仅在小时为8时，而且在doc同时不为空时计算行数。

Answer 3

感谢所有帮助过我的人。有了你的帮助，我制作了追随我的东西。

    DELIMITER $$

CREATE DEFINER=`root`@`localhost` PROCEDURE `hourcounter`(IN datestamp DATE)
BEGIN
SELECT username, 

    COUNT(IF(HOUR(modifytime)=8,1,NULL))  AS '8:30  - 9:00', 
    COUNT(IF(HOUR(modifytime)=9,1,NULL))  AS '9:00 - 10:00',
    COUNT(IF(HOUR(modifytime)=10,1,NULL)) AS '10:00 - 11:00',
    COUNT(IF(HOUR(modifytime)=11,1,NULL)) AS '11:00 - 12:00',
    COUNT(IF(HOUR(modifytime)=12,1,NULL)) AS '12:00 - 1:00',
    COUNT(IF(HOUR(modifytime)=13,1,NULL)) AS '1:00 - 2:00',
    COUNT(IF(HOUR(modifytime)=14,1,NULL)) AS '2:00 - 3:00',
    COUNT(IF(HOUR(modifytime)=15,1,NULL)) AS '3:00 - 4:00',
    COUNT(IF(HOUR(modifytime)=16,1,NULL)) AS '4:00 - 5:00',
    COUNT(docs) 'Total'


FROM claimloans 
WHERE docs != '' and DATE(date) = datestamp 
group by username;

   END

感谢所有帮助过我的人。我从你的答案中学到很多东西!!

使用sproc按小时计算表值

3 个答案: