我正在尝试合并两个没有重复行的表
表1 - modx_site_content
|id|pagetitle|introtext|pub_date|
---------------------------------
|3635| name1 |texttextt|17.02.2015
|3636| name1 |texttextt|18.02.2015
表2 - modx_site_tmplvar_contentvalues
|contentid|tmplvarid|value|
---------------------------
| 3635 | 1 |value1
| 3635 | 1 |value2
| 3636 | 1 |value3
我试图制作所有
|id|title|introtext|publishdate|photo|
--------------------------------------
|3635|name1|texttextt|17.02.2015|value1, value2
|3636|name1|texttextt|18.02.2015|value3
但是当前结果显示dublicate rows id 3535
|id|title|introtext|publishdate|photo|
--------------------------------------
|3635|name1|texttextt|17.02.2015|value1
|3635|name1|texttextt|17.02.2015|value2
|3636|name1|texttextt|18.02.2015|value3
我当前的sql resuest是
SELECT
modx_site_content.id,
pagetitle as 'title',
introtext,
pub_date as 'publishdate',
modx_site_tmplvar_contentvalues.value as 'photo'
FROM `modx_site_content`,
`modx_site_tmplvar_contentvalues`
WHERE parent IN (1153,3271)
AND pub_date>0
AND `contentid`= modx_site_content.id
AND `tmplvarid` IN (10, 15, 19)
Order by `pub_date` DESC LIMIT 20
答案 0 :(得分:2)
您当前问题的解决方案是group by
和group_concat()
:
SELECT c.id, c.pagetitle as title, c.introtext, c.pub_date as publishdate,
group_concat(cv.value) as sphotos
FROM `modx_site_content` c JOIN
`modx_site_tmplvar_contentvalues` cv
ON cv.`contentid`= c.id
WHERE c.parent IN (1153, 3271) AND c.pub_date > 0 AND
`tmplvarid` IN (10, 15, 19)
GROUP BY c.id, c.pagetitle, c.introtext, c.pub_date
Order by c.`pub_date` DESC
LIMIT 20;
我还建议:
join
语法。from
子句中定义表别名。答案 1 :(得分:1)
MySQL有group_concat可能有效(取决于数据类型):
SELECT
modx_site_content.id,
pagetitle as 'title',
introtext,
pub_date as 'publishdate',
group_concat(modx_site_tmplvar_contentvalues.value) as 'photo'
FROM `modx_site_content` JOIN
`modx_site_tmplvar_contentvalues` ON `contentid`= modx_site_content.id
WHERE parent IN (1153,3271)
AND pub_date>0
AND `tmplvarid` IN (10, 15, 19)
GROUP BY modx_site_content.id, pagetitle , introtext, pub_date