Question

我得到了以下警告，运行简单的声明，我很好奇为什么我得到它：

UPDATE `Table1` 
SET `City`='Miami', 
    `ExpDate`='201227', 
    `User`='JDoe', 
    `UpdDate`='2015-02-17 16:11:25' 
WHERE `id` = 61`

以下是Table1结构：

CREATE TABLE `Table1` (
  `id` bigint(20) NOT NULL AUTO_INCREMENT,
  `User` varchar(10) COLLATE utf8_bin DEFAULT NULL,
  `City` varchar(25) COLLATE utf8_bin DEFAULT NULL,
  `ExpDate` varchar(10) COLLATE utf8_bin DEFAULT NULL,
  `UpdDate` datetime DEFAULT NULL,
  PRIMARY KEY (`id`),
  UNIQUE KEY `Unique_Index` (`User`,`City`),
  UNIQUE KEY `id` (`id`),
  KEY `ALT1_IDX_Table1` (`User`,`City`)
) ENGINE=InnoDB AUTO_INCREMENT=64 DEFAULT CHARSET=utf8 COLLATE=utf8_bin;

日志完全错误：

2015-02-17 16:10:08 1548 [Warning] Unsafe statement written to the binary log using statement format since BINLOG_FORMAT = STATEMENT. Statement is unsafe because it invokes a trigger or a stored function that inserts into an AUTO_INCREMENT column. Inserted values cannot be logged correctly. Statement: UPDATE表1 SET {市{1}} {EXPDATE {1}}用户='Miami', {UpdDate {1}} ID为='201227',

Answer 1

最后，错误显示了这里的错误。 Statement is unsafe because it invokes a trigger or a stored function that inserts into an AUTO_INCREMENT column 该错误不在表本身中，错误在触发器或过程中，当此表更新时触发。

1548 [警告]自BINLOG_FORMAT = STATEMENT以来，使用语句格式将不安全语句写入二进制日志

1 个答案: