Base64:java.lang.IllegalArgumentException:非法字符

时间:2015-02-18 12:47:58

标签: java base64 javamail registration

我试图在用户注册后发送确认电子邮件。我为此目的使用JavaMail库和Java 8 Base64 util类。

我按以下方式编码用户电子邮件:

byte[] encodedEmail = Base64.getUrlEncoder().encode(user.getEmail().getBytes(StandardCharsets.UTF_8));
Multipart multipart = new MimeMultipart();
InternetHeaders headers = new InternetHeaders();
headers.addHeader("Content-type", "text/html; charset=UTF-8");
String confirmLink = "Complete your registration by clicking on following"+ "\n<a href='" + confirmationURL + encodedEmail + "'>link</a>";
MimeBodyPart link = new MimeBodyPart(headers,
confirmLink.getBytes("UTF-8"));
multipart.addBodyPart(link);

其中confirmationURL是:

private final static String confirmationURL = "http://localhost:8080/project/controller?command=confirmRegistration&ID=";

然后以这种方式在ConfirmRegistrationCommand中对此进行解码:

    String encryptedEmail = request.getParameter("ID");

    String decodedEmail = new String(Base64.getUrlDecoder().decode(encryptedEmail), StandardCharsets.UTF_8);

    RepositoryFactory repositoryFactory = RepositoryFactory
            .getFactoryByName(FactoryType.MYSQL_REPOSITORY_FACTORY);
    UserRepository userRepository = repositoryFactory.getUserRepository();
    User user = userRepository.find(decodedEmail);

    if (user.getEmail().equals(decodedEmail)) {
        user.setActiveStatus(true);
        return Path.WELCOME_PAGE;
    } else {
        return Path.ERROR_PAGE;
    }

当我试图解码时:

http://localhost:8080/project/controller?command=confirmRegistration&ID=[B@6499375d

我得到了java.lang.IllegalArgumentException: Illegal base64 character 5b

我尝试使用基本的编码/解码器(不是URL编码器)但没有成功。

解决:

问题是下一个 - 在线:

 String confirmLink = "Complete your registration by clicking on following"+ "\n<a href='" + confirmationURL + encodedEmail + "'>link</a>";

我在一个字节数组上调用toString,所以我应该执行以下操作:

String encodedEmail = new String(Base64.getEncoder().encode(
                user.getEmail().getBytes(StandardCharsets.UTF_8)));

感谢 Jon Skeet ByteHamster

5 个答案:

答案 0 :(得分:16)

您的编码文字为[B@6499375d。这不是Base64,在编码时出错了。解码代码看起来不错。

使用此代码将byte []转换为String,然后再将其添加到URL:

String encodedEmailString = new String(encodedEmail, "UTF-8");
// ...
String confirmLink = "Complete your registration by clicking on following"
    + "\n<a href='" + confirmationURL + encodedEmailString + "'>link</a>";

答案 1 :(得分:9)

我遇到此错误,因为我的编码图像以data:image/png;base64,iVBORw0...开头。

This answer让我找到了解决方案:

String partSeparator = ",";
if (data.contains(partSeparator) {
  String encodedImg = data.split(partSeparator)[1];
  byte[] decodedImg = Base64.getDecoder().decode(encodedImg.getBytes(StandardCharsets.UTF_8));
  Path destinationFile = Paths.get("/path/to/imageDir", "myImage.jpg");
  Files.write(destinationFile, decodedImg);
}

答案 2 :(得分:2)

只需使用以下代码即可解决此问题:

JsonObject obj = Json.createReader(new ByteArrayInputStream(Base64.getDecoder().decode(accessToken.split("\\.")[1].
                        replace('-', '+').replace('_', '/')))).readObject();

在上面的代码中replace('-', '+').replace('_', '/')完成了这项工作。有关详细信息,请参阅https://jwt.io/js/jwt.js。我理解了从该链接得到的代码部分的问题:

function url_base64_decode(str) {
  var output = str.replace(/-/g, '+').replace(/_/g, '/');
  switch (output.length % 4) {
    case 0:
      break;
    case 2:
      output += '==';
      break;
    case 3:
      output += '=';
      break;
    default:
      throw 'Illegal base64url string!';
  }
  var result = window.atob(output); //polifyll https://github.com/davidchambers/Base64.js
  try{
    return decodeURIComponent(escape(result));
  } catch (err) {
    return result;
  }
}

答案 3 :(得分:1)

Base64.Encoder.encodeToString方法自动使用ISO-8859-1字符集。

对于我正在编写的加密实用程序,我使用密文输入字符串和Base64对其进行编码以进行传输,然后反转该过程。相关部分如下所示。 注意:我的file.encoding属性在调用JVM时设置为ISO-8859-1,因此也可能有影响。

static String getBase64EncodedCipherText(String cipherText) {
    byte[] cText = cipherText.getBytes();
    // return an ISO-8859-1 encoded String
    return Base64.getEncoder().encodeToString(cText);
}

static String getBase64DecodedCipherText(String encodedCipherText) throws IOException {
    return new String((Base64.getDecoder().decode(encodedCipherText)));
}

public static void main(String[] args) {
    try {
        String cText = getRawCipherText(null, "Hello World of Encryption...");

        System.out.println("Text to encrypt/encode: Hello World of Encryption...");
        // This output is a simple sanity check to display that the text
        // has indeed been converted to a cipher text which 
        // is unreadable by all but the most intelligent of programmers.
        // It is absolutely inhuman of me to do such a thing, but I am a
        // rebel and cannot be trusted in any way.  Please look away.
        System.out.println("RAW CIPHER TEXT: " + cText);
        cText = getBase64EncodedCipherText(cText);
        System.out.println("BASE64 ENCODED: " + cText);
        // There he goes again!!
        System.out.println("BASE64 DECODED:  " + getBase64DecodedCipherText(cText));
        System.out.println("DECODED CIPHER TEXT: " + decodeRawCipherText(null, getBase64DecodedCipherText(cText)));
    } catch (Exception e) {
        e.printStackTrace();
    }

}

输出如下:

Text to encrypt/encode: Hello World of Encryption...
RAW CIPHER TEXT: q$;�C�l��<8��U���X[7l
BASE64 ENCODED: HnEPJDuhQ+qDbInUCzw4gx0VDqtVwef+WFs3bA==
BASE64 DECODED:  q$;�C�l��<8��U���X[7l``
DECODED CIPHER TEXT: Hello World of Encryption...

答案 4 :(得分:0)

我的Linux Jenkins从属服务器出现此错误。通过将节点从“已知主机文件验证策略”更改为“非验证文件验证策略”来解决此问题。