Question

我有这个HQL查询，我需要从floor(e.timestamp/(1000*60*60*24))*60*60*24返回的值为long，但使用cast（）不起作用，因为mysql不接受强制转换为BigInt或Long。我找不到正确的方法。

SELECT new DayEvent(
e.apiProxyId, 
e.apiKey, 
e.methodId,
floor(e.timestamp/(1000*60*60*24))*60*60*24, 
sum(e.count), 
e.region)                        
FROM Event AS e 
WHERE e.timestamp <= :endTimestamp 
AND e.timestamp >= :startTimestamp 
GROUP BY floor(e.timestamp/(1000*60*60*24)), e.methodId, e.apiKey, e.region, e.apiProxyId`

Answer 1

Hibernate支持在HQL中进行强制转换：

SELECT new DayEvent(
e.apiProxyId, 
e.apiKey, 
e.methodId,
cast(floor(e.timestamp/(1000*60*60*24))*60*60*24 as long), 
sum(e.count), 
e.region)                        
FROM Event AS e 
WHERE e.timestamp <= :endTimestamp 
AND e.timestamp >= :startTimestamp 
GROUP BY floor(e.timestamp/(1000*60*60*24)), e.methodId, e.apiKey, e.region, e.apiProxyId

使用MySQL 5.5在Hibernate HQL中从Int转换为Long

1 个答案: