Question

HTML代码发布在最后，我想选择“OF”元素。这是CSS选择器

Elements position = doc.select("#content > table:nth-child(4) > tbody > tr > td:nth-child(1) > table > tbody > tr:nth-child(1) > td > div:nth-child(5) > strong:nth-child(4)");

for (Element p : position) {
    System.out.println(p);
}

这是输出

p returns "<strong>Position:</strong>"
p.text() returns "Position:"

当我突出显示“OF”时，

来自chrome的xpath：

//*@id="content"]/table[1]/tbody/tr/td[1]/table/tbody/tr[1]/td/div[3]/text()[4]

HTML代码

<div style="font-size: 10pt; padding-left:5px;">
     <strong>Birthdate:</strong> 8/7/1991 (23 y, 6 m, 10 d) &nbsp;&nbsp;&nbsp;&nbsp;
     <strong>Bats/Throws:</strong> R/R &nbsp;&nbsp;&nbsp;&nbsp;
     <strong>Height/Weight:</strong> 6-2/230 &nbsp;&nbsp;&nbsp;&nbsp;
     <strong>Position:</strong> OF<br /><b>Drafted:</b> <a href="statss.aspx?playerid=10155&position=OF#draft" style="text-decoration:none;">2009 June Amateur Draft - Round: 1, Pick: 25, Overall: 25, Team: Los Angeles Angels</a><br />
     <strong>Contract:</strong> <a href="statss.aspx?playerid=10155&position=OF#contract" style="text-decoration:none;">$144.5M / 6 Years (2015 - 2020)</a>
</div>
<div style="font-size: 10pt; padding-left:5px;">
      <strong>Birthdate:</strong> 8/7/1991 (23 y, 6 m, 10 d) &nbsp;&nbsp;&nbsp;&nbsp;
      <strong>Bats/Throws:</strong> R/R &nbsp;&nbsp;&nbsp;&nbsp;
      <strong>Height/Weight:</strong> 6-2/230 &nbsp;&nbsp;&nbsp;&nbsp;
      <strong>Position:</strong> OF<br /><b>Drafted:</b> <a href="statss.aspx?playerid=10155&position=OF#draft" style="text-decoration:none;">2009 June Amateur Draft - Round: 1, Pick: 25, Overall: 25, Team: Los Angeles Angels</a><br />
      <strong>Contract:</strong> <a href="statss.aspx?playerid=10155&position=OF#contract" style="text-decoration:none;">$144.5M / 6 Years (2015 - 2020)</a>
</div>

如果有人有兴趣，这是页面 http://www.fangraphs.com/statss.aspx?playerid=10155&position=OF

Answer 1

您无法为文本节点编写css选择器（“OF”是目标div元素中包含的第四个文本节点）。所以你需要像这样以编程方式获取（需要jsoup＆gt; = 1.6.2）：

// select container div element
Elements position = doc.select("#content > table:nth-child(4) > tbody > tr > td:nth-child(1) > table > tbody > tr:nth-child(1) > td > div:nth-child(5)");
// extract the element from the list returned
Element element = ....
// TODO will need to check that the List exists and have at least four elements here
TextNode ofNode = element.textNodes().get(4);
ofNode.text(); // this will contain "OF"

用于文本节点xpath的Jsoup CSS选择器

1 个答案: