查找所有IS具有来自另一个表的所有值

Question

在三个表中：

Actors:
+------------------+
| id_a | actor_name|
+------------------+
|   1  | AAA       |
|   2  | Bbb       |
|   3  | Ccc       |
|   4  | Ddd       |
|   5  | Eee       |
+------------------+

Movies:
+----------------+
| id_m | mov_name|
+----------------+
| 1    |   LoR   |
| 2    |  Thron  |
| 3    |   ZsT   |
+----------------+

actors_in_movies:
+-------------+
| id_m | id_a |
+-------------+
| 1    |  1   |
| 1    |  3   |
| 1    |  5   |
| 2    |  1   |
| 2    |  3   |
| 3    |  2   |
| 3    |  3   |
| 3    |  4   |
| 3    |  5   |
+-------------+

可以编写一个查询来获取：所有来自查询的演员的电影吗？

示例：SELECT id_m WHERE id_a IN（1,3,4,5），应该给出：

+------+
| id_m |
+------+
|  1   |
|  2   |
+------+

然而.. SELECT id_m WHERE id_a IN（1,9）应该给出NULL。

我尝试了类似的查询：Finding ID having all values (mySQL, SQL)，写了类似的内容：

SELECT id_m, count(*), group_concat(id_a) as all_act 
FROM actors_in_movies 
WHERE
 id_m IN (SELECT id_m FROM actors_in_movies WHERE id_a = 1)
AND
 id_m IN (SELECT id_m FROM actors_in_movies WHERE id_a = 3)
AND
 id_m IN (SELECT id_m FROM actors_in_movies WHERE id_a = 5)
GROUP BY (id_m)
HAVING count(*) <= 3

它只显示一部电影（id_m：1）， 如果我使用'或'它几乎可以， 但是对我来说重要的是让所有电影都来自查询演员， 演员或更少的演员，从来没有演员错过查询的电影。 怎么写？

Answer 1

使用group by和having：

SELECT id_m
FROM table
WHERE id_a IN (1, 9) 
GROUP BY id_m
HAVING COUNT(DISTINCT id_a) = 2;