Question

我有一个Java的工作代码，但我想在scala中转换相同的代码。这就是我的Java代码：

public class ScannerError extends RuntimeException {
  public ScannerError(String expected, Token look) {
    super(look.fileName + ":" + look.lineNumber + 
          " Expected: " + expected + 
          " Found: " + look);
  }
}

我在scala中将上面的代码转换为：

import scala.collection.JavaConversions._
object ScannerError(expected: String, look: Token) extends RuntimeException(look.fileName + ":" + look.lineNumber + " Expected: " + 
expected + " Found: " + look)

scala代码在expected:时出错。错误消息是＆＃34;特征或对象可能没有参数＆＃34;。

Answer 1

object是单例模式的scala编码，单例不按定义获取参数。改为使用class：

class ScannerError(expected: String, look: Token)
  extends RuntimeException(s"${look.fileName}: ${look.lineNumber} Expected: $expected Found: $look")

将java转换为scala

1 个答案: