Question

这是我的代码：

func submitLacunaRequest (#module: String, method: String, parameters: AnyObject, completion: (responseObject: AnyObject!, error: NSError!) -> (Void)) -> NSURLSessionTask? {
        let session = NSURLSession.sharedSession()
        let url = NSURL(string: "https://us1.lacunaexpanse.com").URLByAppendingPathComponent(module)
        let request = NSMutableURLRequest(URL: url)
        request.HTTPMethod = "POST"
        request.setValue("application/json-rpc", forHTTPHeaderField: "Content-Type")

缺少参数＆＃34; host＆＃34;的参数在电话中。它发生在这条线上。

 let url = NSURL(string: "https://us1.lacunaexpanse.com").URLByAppendingPathComponent(module)

任何想法如何解决这个问题？

谢谢！

Answer 1

这种错误令人误解。问题不是缺少参数，而是您如何访问NSURL。您必须添加?才能访问可选项，因为NSURL可以为null，或者您打开它：

//First option:
let url = NSURL(string: "https://us1.lacunaexpanse.com")?.URLByAppendingPathComponent(module)

//Unwrapping
if let url = NSURL(string: "https://us1.lacunaexpanse.com")?.URLByAppendingPathComponent(module){
    let request = NSMutableURLRequest(URL: url)
    request.HTTPMethod = "POST"
    request.setValue("application/json-rpc", forHTTPHeaderField: "Content-Type")
}

Swift - 缺少参数＆＃39; host＆＃39;在电话中

1 个答案: