Question

this piece of php code如何与多个收件人合作？

仅当$to只有一个地址时才有效，例如：

$to = 'aa@bb.com';

修改

如果电子邮件地址位于同一个域中，则有效。例如，如果网站为www.example.com，则xxx@example.com等电子邮件将有效，但y yy@other.com赢了

解决方案

PHPMailer的。它提供了一种配置SMTP的简便方法。

以下是初始代码

<?php

//define the receiver of the email
$to = 'aa@bb.com, cc@dd.com, ee@ff.com';

// array with filenames to be sent as attachment
$files = array("a.zip","b.c","a.html");

// email fields: to, from, subject, and so on
$from = "mail@mail.com"; 
$subject ="My subject"; 
$message = "My message";

// boundary 
$semi_rand = md5(time()); 
$mime_boundary = "==Multipart_Boundary_x{$semi_rand}x"; 

// headers for attachment 
$headers = "From: $from";
$headers .= "\nMIME-Version: 1.0\n" . "Content-Type: multipart/mixed;\n" . " boundary=\"{$mime_boundary}\""; 

// multipart boundary 
$message = "This is a multi-part message in MIME format.\n\n" . "--{$mime_boundary}\n" . "Content-Type: text/plain; charset=\"iso-8859-1\"\n" . "Content-Transfer-Encoding: 7bit\n\n" . $message . "\n\n"; 
$message .= "--{$mime_boundary}\n";

// preparing attachments
for($x=0;$x<count($files);$x++){
    $file = fopen($files[$x],"rb");
    $data = fread($file,filesize($files[$x]));
    fclose($file);
    $data = chunk_split(base64_encode($data));
    $message .= "Content-Type: {\"application/octet-stream\"};\n" . " name=\"$files[$x]\"\n" . 
    "Content-Disposition: attachment;\n" . " filename=\"$files[$x]\"\n" . 
    "Content-Transfer-Encoding: base64\n\n" . $data . "\n\n";
    $message .= "--{$mime_boundary}\n";
}

// send

$ok = @mail($to, $subject, $message, $headers); 
if ($ok) { 
    echo "<p>mail sent to $to!</p>"; 
} else { 
    echo "<p>mail could not be sent!</p>"; 
} 

?>

以下是最终代码

// PHPMailer
$mail = new PHPMailer;

// setting up PHPMailer
$mail->isSMTP();
$mail->Host = 'host.com';
$mail->SMTPAuth = false;
$mail->Port = xx;

$mail->setFrom($_POST['email'], $_POST['name']);
$mail->Subject = $_POST['subject'];
$mail->msgHTML($_POST['message']);

foreach($contacts as $contact)
    $mail->addAddress($contact['email']);

// If the user has attached some files
foreach ($_FILES as $file)
    $mail->addAttachment($file['tmp_name'], basename($file['name']));

$response = array("status" => $mail->send() ? "sent" : "error");

echo json_encode($response);

Answer 1

您需要使用正确的RFC 2822格式化。

不要使用@，因为你不知道错误是什么。如果您格式化邮件格式为＆＃34; user@example.com,alotheruser@example.com"它是正确的，你需要在其他地方搜索问题。

您还可以在http://php.net/manual/en/function.mail.php#example-3493页面上看到示例＃4。

Answer 2

虽然这不是对您的问题的直接回复，但您可以通过使用预先存在的电子邮件发送库来避免麻烦：

PHPMailer的 https://github.com/PHPMailer/PHPMailer

或simplesmtp https://bitbucket.org/ghorwood/simplesmtp/

Php邮件不能与多个收件人一起使用

2 个答案: