检查字符串PHP中的确切句子

Question

我正在尝试检查字符串是否包含确切的句子。

示例：

 $sentence = "welcome to";
 $string = "hello and welcome to my website.";
 if(strpos($string, $sentence) !== false) {
    //found PART of "welcome to" in the $string
    //Only want it to come back true is it contains "welcome to".
 }

我现在想检查它是否含有exactelly＆＃34;欢迎来到＆＃34;。 不是＆＃34;来＆＃34;或者＆＃34;欢迎＆＃34; ... $句子的确切价值。 它也需要是动态的。因此，从变量中检查可能包含任何句子的变量。

感谢。马丁。

Answer 1

使用preg_match()会更好地获得完全匹配并使用\b字边界。

$string = "hello and welcome to my website.";
if ( preg_match("~\bwelcome to\b~",$string) ){

  echo "Match found.";
  }
else{
  echo "No match found.";
 }

---

在做的时候：

~\bcome to\b~

不会匹配。

---

修改

// will match
$sentence = "welcome to"; 

// will not match
// $sentence = "come to"; 

$string = "hello and welcome to my website.";

if(preg_match("~\b".$sentence."\b~", $string)){
  echo "An exact match was found.";
  }
else{
  echo "No exact match was found.";
  }

---

要添加不区分大小写，请使用i开关：

if (preg_match("#\b".$sentence."\b#i",$string))

Answer 2

$sentence = "welcome to";
$string = "Hello and welcome to my website";

if( strstr($sentence, $string)) { 
    // Your code here if $sentence contains $string
} 
else{
    // If no contains
}