Question

我有这张桌子：

CREATE TABLE IF NOT EXISTS `usage` (
  `id` int(11) unsigned NOT NULL AUTO_INCREMENT,
  `host_id` int(10) unsigned NOT NULL,
  `time_id` int(10) unsigned NOT NULL,
  `state` enum('LinuxTU','LinuxExt','View','Browser','Idle','Offline') CHARACTER SET latin1 NOT NULL DEFAULT 'Offline',
  PRIMARY KEY (`id`),
  KEY `host_id` (`host_id`),
  KEY `time_id` (`time_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=utf8 AUTO_INCREMENT=12998 ;

此表存储不同计算机的状态信息。

我实际上可以得到这个。哪个存储我需要的值但不是正确的格式：

SELECT time_id, state, COUNT(state) statecount
FROM `usage` u
GROUP BY time_id, state

结果：

time_id  state      statecount
      7  LinuxTU            20
      7  LinuxExt           11
      7  View               51
      7  Browser             5
      7  Idle               67
      7  Offline            83
      8  LinuxTU            22
      8  LinuxExt           10
      8  View               55
      8  Browser             4
      8  Idle               66
      8  Offline            80

我希望得到一个带有计数状态值的矩阵，如下所示：

time_id   LinuxTU   LinuxExt   View   Browser   Idle   Offline
      7        20         11     51         5     67        83
      8        22         10     55         4     66        80

我怎么能得到这个？

Answer 1

好的，数据透视表是关键。也许有一个没有子查询的查询，但我没有找到它。此查询对列更改不灵活。但它有效......

SELECT time_id,
    SUM(IF(state='LinuxTU', statecount, NULL)) AS LinuxTU,
    SUM(IF(state='LinuxExt', statecount, NULL)) AS LinuxExt,
    SUM(IF(state='View', statecount, NULL)) AS View,
    SUM(IF(state='Browser', statecount, NULL)) AS Browser,
    SUM(IF(state='Idle', statecount, NULL)) AS Idle,
    SUM(IF(state='Offline', statecount, NULL)) AS Offline
FROM (
    SELECT time_id, state, COUNT(state) statecount
    FROM `usage` u
    GROUP BY time_id, state
) AS subtab
GROUP BY time_id

如何将多行转换为一行？

1 个答案: