Question

我正在尝试开发一个JS函数，该函数根据之前下拉列表中的选择创建一个新的下拉列表。基本上是一个下拉菜单，根据州的选择选择城市列表。有人有什么建议吗？

这是我正在使用的javascript：

function city() {
var opt = document.getElementById('State');
var sel = opt.options[opt.selectedIndex].value;
var dropdown = document.getElementById('City');
document.write("<?php mysqli_select_db($GLOBALS['SSDN'],$database_SSDN);     $query_City = 'SELECT * FROM city WHERE State = sel ORDER BY City ASC'; $City = mysqli_query($GLOBALS['SSDN'],$query_City) or die(mysql_error()); while ($row_City = mysqli_fetch_array($City, MYSQL_ASSOC)) ?>");

var o = document.createElement('option');
o.text = document.write("<?php echo $row_City['City'];?>");
o.value = document.write("<?php echo $row_City['City'];?>");
dropdown.options.add(o);
}

这是html：

       <td><select name="State" class="Field" id="State">
      <?php
      while ($row_Recordset1 = mysqli_fetch_array($Recordset1, MYSQL_ASSOC)) {
          ?>
          <option value = "<?php echo $row_Recordset1['State'];?>"><?php echo $row_Recordset1['State'];?></option>
          <?php
      }
      ?>
    </select></td>
  </tr>
  <tr height="50">
    <td><div align="right" class="Label">Select New Rehbar City :</div></td>
    <td>&nbsp;</td>
    <td><select name="City" class="Field" id="City" onfocus="City();">

    </select></td>
  </tr>

Answer 1

我记得2011年的这个：http://tutorialzine.com/2011/11/chained-ajax-selects-jquery/

它被称为链式选择框。上面的链接提供了有关如何实现它的教程。看看它也许它会帮助你。

Answer 2

Javascript是一种客户端脚本（编程）语言，PHP是一种服务器端编程语言，这意味着当页面已经刷新到客户端浏览器中时，您无法运行PHP代码，并且只能在页面运行时运行Javascript代码已经加载了！

这些行没有意义，也不会给你想要的结果：

document.write("<?php mysqli_select_db($GLOBALS['SSDN'],$database_SSDN);     $query_City = 'SELECT * FROM city WHERE State = sel ORDER BY City ASC'; $City = mysqli_query($GLOBALS['SSDN'],$query_City) or die(mysql_error()); while ($row_City = mysqli_fetch_array($City, MYSQL_ASSOC)) ?>");
o.text = document.write("<?php echo $row_City['City'];?>");
o.value = document.write("<?php echo $row_City['City'];?>");

将您的选项（数据）放在javascript变量中，然后在脚本中使用它们，如下所示：

<script>
var myOptions = [
    <?php
    // Select and fetch the data from database
    // Loop over your selected data and flush them into your javascript array
    while ($row_City = mysqli_fetch_array($City, MYSQL_ASSOC)){
        // if still have data:
        ?>'<?php echo $row_City["field_name"] ?>',<?php
        // else:
        ?>'<?php echo $row_City["field_name"] ?>'<?php
    }
    ?>
];

for (option in myOptions){
    // add each option to your drop down element
}

</script>

使用基于mysqli创建动态下拉列表

2 个答案: