Sql Server跨列检索重复的行

Question

表1

ColumnA - Column B   Column C

111         Null        AA
111         Null        BB
222         Null        CC
333         555,222     DD
444         Null        EE
666         777         FF
888         777         GG

我需要打印所有行

其中A列中的数字超过两次 A列中的数字与b列中的数字匹配且出现次数不止一次（A列上的第3行与b列的第4行匹配）

预期输出

111         Null        AA
111         Null        BB
222         Null        CC
333         555,222     DD

Answer 1

要从表中获取不同的记录，您可以在查询中使用带有字段名称

的distinct关键字

  

从Table1中选择不同的ColumnA，B列

Answer 2

样本表

CREATE TABLE #TEMP(COLUMNA INT,COLUMNB VARCHAR(30),COLUMNC VARCHAR(30))

INSERT INTO #TEMP
SELECT 111,         Null,        'AA'
UNION ALL
SELECT 111,         Null,        'BB'
UNION ALL
SELECT 222,         Null,        'CC'
UNION ALL
SELECT 333,         '555,222',     'DD'
UNION ALL
SELECT 444,         Null,        'EE'
UNION ALL
SELECT 666,         '777',         'FF'
UNION ALL
SELECT 888,         '777',         'GG'

<强> QUERY

我在查询中写了逻辑

;WITH CTE AS
(
    -- Get the CSV as rows and count the occurance of ColumnA
    SELECT COLUMNA,LTRIM(RTRIM(Split.a.value('.', 'VARCHAR(100)'))) 'COLUMNB',COLUMNC,
    COUNT(COLUMNA) OVER(PARTITION BY COLUMNA) CNT 
    FROM  
    (
         -- Select the values to convert into rows from CSV
         SELECT COLUMNA,
         CAST ('<M>' + REPLACE(ISNULL(COLUMNB,''), ',', '</M><M>') + '</M>' AS XML) AS Data,
         COLUMNC 
         FROM #TEMP     
    ) AS A 
    CROSS APPLY Data.nodes ('/M') AS Split(a)
)
-- Find the rows where number of each unique item in ColumnA > 1
-- and ColumnA element exists in ColumnB
SELECT DISTINCT T.*
FROM CTE C
JOIN #TEMP T ON C.COLUMNA=T.COLUMNA 
WHERE CNT > 1
OR C.COLUMNA IN (SELECT DISTINCT COLUMNB FROM CTE)

• Click here查看结果

<强> RESULT

修改

如果您想在两个条件都满足时获取记录，请在最后一行使用AND代替OR，即

AND C.COLUMNA IN (SELECT DISTINCT COLUMNB FROM CTE)