Question

我有一张桌子，由于特定原因，我必须使用自定义表格列作为ID：

表格表示具有列ID，我想使用列edavis_id而不是id。

#app/models/representation.rb:  

class Representation < ActiveRecord::Base
  attr_accessible :people_attributes, :name, :country_id, :rep_type_id, :address, :address_postal, :phone, :email, :fax, :homepage, :consular_district, :botschaftsfunk, :ivs, :ivpn, :idirect

  belongs_to :country
  belongs_to :rep_type

  has_many :people
  has_many :representation_telephones, foreign_key: :representation_id

  accepts_nested_attributes_for :people

  validates_uniqueness_of :remedy_site_id, allow_nil: true

  has_many :device_representation_relations
  has_many :devices, :through => :device_representation_relations

  delegate :name_de, to: :rep_type, prefix: true, allow_nil: true
  delegate :iso_code, to: :country, prefix: true, allow_nil: true
  # omitted...
end

我如何告诉rails使用edavis_id作为id（而不是常规表id）？

Answer 1

尝试：

class Representation < ActiveRecord::Base
  self.primary_key = :edavis_id
  #        
end

http://ruby-journal.com/how-to-override-default-primary-key-id-in-rails/

Answer 2

只需添加：

 class Representation < ActiveRecord::Base
   self.primary_id = :edavis_id
   #...
 end

Rails 3：我如何使用自定义表列作为id而不是常规表id？

2 个答案: