如何让所有提交的内容属于特定用户? 试试这个:
$user=User::find(1);
dd($user->submissions);
投掷错误:
Call to undefined method Illuminate\Database\Query\Builder::hasMany()
我是否必须遍历模型?
以下是模型:
class User extends Eloquent implements ConfideUserInterface, BillableInterface
{
public function categories()
{
return $this->hasMany('Category');
}
public function forms()
{
return $this->hasManyThrough('App\Models\Form', 'Category');
}
public function submissions()
{
return $this->hasMany('Category')->hasMany('Form')->hasMany('Submission');
}
}
class Category extends \Eloquent {
public function user()
{
return $this->belongsTo('User');
}
public function forms()
{
return $this->hasMany('App\Models\Form');
}
public function submissions()
{
return $this->hasManyThrough('Submission', 'App\Models\Form', 'id', 'form_id');
}
}
namespace App\Models;
class Form extends \Eloquent {
public function user()
{
return $this->category->user();
}
public function category()
{
return $this->belongsTo('Category');
}
public function submissions()
{
return $this->hasMany('Submission');
}
}
class Submission extends \Eloquent {
public function user()
{
return $this->form->category->user();
}
public function category()
{
return $this->form->category();
}
public function form()
{
return $this->belongsTo('App\Models\Form');
}
}
答案 0 :(得分:1)
对于链接关系而言,这并没有真正发挥作用......
你能做什么,是这样的:
$submissions = Submission::whereHas('form.category.user', function($q){
$q->where('id', 1);
})->get();
注意具有嵌套关系的whereHas
仅在最新的Laravel 4版本中添加。请务必composer update
。
答案 1 :(得分:0)
如果我没有错误地提出你的问题,你需要正确定义关系。
根据laravel 4.2,您可以使用以下类型的代码来定义关系:
class User extends \Eloquent implements ConfideUserInterface, BillableInterface{
//...
public function submissions(){
return $this->hasMany('Submission');
}
}
//...
class Submission extends \Eloquent {
public function user()
{
return $this->belongsTo('User');
}
//...
}
要进一步阅读,请查看:http://laravel.com/docs/4.2/eloquent#relationships