Question

我正在尝试检查并查看test_list1的每个字符串中是否找到test_list2中的字符串。如果test_list2中存在test_list2中的字符串，那么我想将1添加到新列表中，否则将0添加到同一个新列表中。

所以：

test_list1 = [['Happy', 'Dog'], ['Sad', 'Dog'], ['Dog', 'Dog'], ['Angry', 'Dog']]
test_list2 = ['Happy', 'Sad', 'Angry']
new_list = []

def emotion_detection(x, y):
    for i in x:
        if i in y:
            new_list.append(1)
        if i not in y:
            new_list.append(0)
    print new_list

返回：[0,0,0,0]，当我认为它应该返回[1,1,0,1]

提前感谢您的帮助！

Answer 1

这是你期望的逻辑行为吗？

test_list1 = [['Happy', 'Dog'], ['Sad', 'Dog'], ['Dog', 'Dog'], ['Angry', 'Dog']]
test_list2 = ["Happy", "Sad", "Angry"]
new_list = []

def emotion_detection(x, y):
    for i in x:
        for string in i:
            if string in y:
                new_list.append(1)
                break
        else:
            new_list.append(0)
    print new_list

Answer 2

emotions  = set(["Happy", "Sad", "Angry"])
sentences = ['Happy Dog', 'Sad Dog', 'Dog Dog', 'Angry Dog']

def is_emotional(sentence):
    words = sentence.split()
    return bool(emotions.intersection(words))

sentence_emotions = [is_emotional(sentence) for sentence in sentences]
# gives [True, True, False, True]

编辑：Hackaholic对any有个好主意，但我会把它写成

def is_emotional(sentence):
    return any(word in emotions for word in sentence.split())

这可能会更快，特别是对于长句，因为一旦找到情感词，它就会停止。

Answer 3

test_list1 = [['Happy', 'Dog'], ['Sad', 'Dog'], ['Dog', 'Dog'], ['Angry', 'Dog']]
test_list2 = ["Happy", "Sad", "Angry"]
new_list = []

for element in test_list1:
    if element[0] in test_list2:
        new_list.append(1)
    else:
        new_list.append(0)
print new_list

而不是使用i，请使用i[0]这是情感的索引！

Answer 4

尝试这样：

>>> test_list1 = [['Happy', 'Dog'], ['Sad', 'Dog'], ['Dog', 'Dog'],['Angry', 'Dog']]
>>> test_list2 = ["Happy", "Sad", "Angry"]
>>> [any(set(x)&set(test_list2)) for x in test_list1]
[True, True, False, True]

Answer 5

使用列表推导：

new_list = [k[0] in test_list2 for k in test_list1]

检查列表中的字符串是否存在于不同的字符串Python列表中

5 个答案: