Question

我有以下高分榜：

CREATE TABLE IF NOT EXISTS `highscores` (
  `lid` int(11) NOT NULL,
  `username` varchar(15) NOT NULL,
  `userid` int(6) NOT NULL,
  `score` int(16) NOT NULL,
  `dateadded` timestamp NOT NULL default CURRENT_TIMESTAMP,
  PRIMARY KEY  (`lid`,`username`),
  KEY `score` (`lid`,`score`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1;

并提出以下问题：

1-列出最高分的用户

SELECT
   h.userid,h.username ,count(h.username)
FROM
    highscores h inner join
    (select lid, min(score) as minscore,COUNT( * ) AS totalScores
     FROM highscores GROUP BY lid) t on h.lid = t.lid and h.score = t.minscore
GROUP BY h.username ORDER BY `count(h.username)`  DESC

2-列出提交分数最多的用户

SELECT username, COUNT( * ) 
FROM highscores
GROUP BY username
ORDER BY COUNT( * ) DESC

我想要的是一个查询，它同时获得用户总得分和提交的分数，按照得分最高的用户排序。

等等（不确定如何格式化表格） -

-Username - 高分 - submittedscores

-John --------- 65 -------------- 755

-Jill ------------ 42 -------------- 1435

Answer 1

select h.username, h.highScores, s.submittedScores
from
(
    SELECT
        h.username, count(h.username) as highScores
    FROM
        highscores h inner join
        (select lid, min(score) as minscore,COUNT( * ) AS totalScores
         FROM highscores GROUP BY lid) t on h.lid = t.lid and h.score = t.minscore
    GROUP BY h.username
) as h
inner join
(
    SELECT username, COUNT(*) as submittedScores
    FROM highscores
    GROUP BY username
) as s
    on s.username = h.username
order by h.highScores desc, s.submittedScores

我刚拿走了你的两个结果并将它们与内部联接结合起来。不是你需要的吗？

我还没有倾注你的两个问题所以很可能是一个更简单的版本。

Mysql获得高分和所有提交的分数

1 个答案: