Question

我很抱歉我的英语，但无论如何：我有一个庞大的，如“[arg1，”start，of，text，in，quotes“，arg2]”来自命令“somecommand arg1”引号“”的文本开头。我被空格字符串分割了，但这是不正确的。我想把引号中的所有内容作为数组中的一个位置：

鉴于：arg1“引号中的文字开头”arg2
之前：[arg1，“start，of，text，in，quotes”，arg2]
之后：[arg1，“引号中的文字开头”，arg2]

它不仅需要使用一个双引号。这是我的代码：

public static String[] fixArguments(String[] arr) {
        String[] rarr = new String[arr.length];
        System.out.println("===========================");
        System.out.println("fixArguments|arr:"+Arrays.toString(arr));
        System.out.println("fixArguments|rarr:"+Arrays.toString(rarr));
        /*for(int i=0; i<arr.length; i++) {
            if(i < start) rarr[i] = arr[i];
            else if(i > end) rarr[i] = arr[i-(end-start)];
            else {
                rarr[i] = StringUtils.join(Arrays.copyOfRange(arr, start, end), " ");
            }
        }*/

        int start = -1;
        int end = -1;
        int lastnull = -1;
        for(int i=0; i<arr.length; i++) {
            if(rarr[i] == null && lastnull == -1) lastnull = i;
            System.out.println("fixArguments|for:"+i+"|start:"+start);
            System.out.println("fixArguments|for:"+i+"|end:"+end);
            System.out.println("fixArguments|for:"+i+"|arr[i]:"+arr[i]);
            if((arr[i].equalsIgnoreCase("\"") || arr[i].startsWith("\"")) && start == -1) start = i;
            else if((arr[i].equalsIgnoreCase("\"") || arr[i].endsWith("\"")) && start != -1) {
                rarr[start] = StringUtils.join(Arrays.copyOfRange(arr, start, i+start), " ");
                System.out.println(Arrays.asList(arr));
                System.out.println(i);
                System.out.println(Arrays.asList(Arrays.copyOfRange(arr, start, i+start)));
                System.out.println(arr[i]);

                rarr[start] = rarr[start].substring(1, rarr[start].length()-1);
                System.out.println("fixArguments|for:"+i+"|rar[start]"+rarr[start]);
                start = -1;
                end = i;
            } else {
                rarr[start+1] = arr[end+1];
                System.out.println(rarr[start+1]);
                lastnull = -1;
            }
        }
        System.out.println("=================================");
        return rarr;
    }

Answer 1

现在操作List比数组更容易，所以我插入了一个转换机制。您可能希望专门使用List表单。

public static List<String> fixArguments(List<String> args) {
    List<String> fixed = new ArrayList<>();
    StringBuilder building = new StringBuilder();
    boolean build = false;
    for (String arg : args) {
        // A " at the start switches to building.
        if (arg.charAt(0) == '\"') {
            build = true;
            building.setLength(0);
        }
        if (build) {
            if (building.length() > 0) {
                building.append(" ");
            }
            building.append(arg);
        } else {
            fixed.add(arg);
        }
        // A " at the end stops the building.
        if (arg.charAt(arg.length() - 1) == '\"') {
            fixed.add(building.toString());
            build = false;
        }
    }
    return fixed;
}

public static String[] fixArguments(String[] arguments) {
    // Roll the array into a List
    List<String> args = Arrays.asList(arguments);
    List<String> fixed = fixArguments(args);
    String[] results = new String[fixed.size()];
    // Roll out the results back into an array.
    for (int i = 0; i < results.length; i++) {
        results[i] = fixed.get(i);
    }
    return results;
}

public void test() {
    String[] arguments = new String[]{"One", "\"Two,", "Three,", "Four\"", "Five"};
    String[] fixed = fixArguments(arguments);
    System.out.println("Before: " + Arrays.asList(arguments));
    System.out.println("After : " + Arrays.asList(fixed));
}

移动和固定阵列

1 个答案: