我必须在/res/raw/
文件夹中打开一个文件,但似乎android,并不能识别路径。
这是我的代码:
public static void openRec()
{
//this is the wav file that I have to analyze
File file = new File("/res/raw/chirp.wav");
try {
FileInputStream in = new FileInputStream(file);
chirp = new byte[(int) file.length()];
in.read(chirp);
Log.d("xxx", "" + chirp.length);
in.close();
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
编辑: 我有另一个方法openRec,其中路径作为参数传递:
public static void openRec(String path) {
File file = new File(path);
try {
FileInputStream in = new FileInputStream(file);
recording = new byte[(int) file.length()];
in.read(recording);
Log.d("xxx", "" + recording.length);
in.close();
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
我会使用/ res / raw中的ffile执行相同的操作。我怎么做?
答案 0 :(得分:2)
以这种方式使用
public static void openRec()
{
//this is the wav file that I have to analyze
try {
InputStream in = getResources().openRawResource(R.raw.chirp);
chirp = new byte[(int) file.length()];
in.read(chirp);
Log.d("xxx", "" + chirp.length);
in.close();
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}