Question

我正在尝试为我的公司设置测试环境。他们选择使用JPA连接到那里的microsoft sql server数据库。问题是我重新创建数据库并使用他们的源代码无法连接到它。这是我得到的junit错误（仍然是方言，而不是junit）

[junit] com.companyname.kernel.persistence.jpa.UnicodeSQLServerDialect.registerColumnType(IILjava/lang/String;)V
[junit] java.lang.NoSuchMethodError: com.companyname.kernel.persistence.jpa.UnicodeSQLServerDialect.registerColumnType(IILjava/lang/String;)V
[junit]     at com.companyname.kernel.persistence.jpa.UnicodeSQLServerDialect.<init>(Unknown Source)
[junit]     at java.lang.reflect.Constructor.newInstance(Constructor.java:408)
[junit]     at java.lang.Class.newInstance(Class.java:438)
[junit]     at org.hibernate.boot.registry.selector.internal.StrategySelectorImpl.resolveDefaultableStrategy(StrategySelectorImpl.java:159)
[junit]     at org.hibernate.boot.registry.selector.internal.StrategySelectorImpl.resolveStrategy(StrategySelectorImpl.java:136)
[junit]     at org.hibernate.engine.jdbc.dialect.internal.DialectFactoryImpl.constructDialect(DialectFactoryImpl.java:78)
[junit]     at org.hibernate.engine.jdbc.dialect.internal.DialectFactoryImpl.buildDialect(DialectFactoryImpl.java:68)
[junit]     at org.hibernate.engine.jdbc.internal.JdbcServicesImpl.configure(JdbcServicesImpl.java:165)
[junit]     at org.hibernate.boot.registry.internal.StandardServiceRegistryImpl.configureService(StandardServiceRegistryImpl.java:111)
[junit]     at org.hibernate.service.internal.AbstractServiceRegistryImpl.initializeService(AbstractServiceRegistryImpl.java:234)
[junit]     at org.hibernate.service.internal.AbstractServiceRegistryImpl.getService(AbstractServiceRegistryImpl.java:206)
[junit]     at org.hibernate.cfg.Configuration.buildTypeRegistrations(Configuration.java:1887)
[junit]     at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1845)
[junit]     at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl$4.perform(EntityManagerFactoryBuilderImpl.java:852)
[junit]     at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl$4.perform(EntityManagerFactoryBuilderImpl.java:845)
[junit]     at org.hibernate.boot.registry.classloading.internal.ClassLoaderServiceImpl.withTccl(ClassLoaderServiceImpl.java:398)
[junit]     at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.build(EntityManagerFactoryBuilderImpl.java:844)
[junit]     at org.hibernate.jpa.HibernatePersistenceProvider.createEntityManagerFactory(HibernatePersistenceProvider.java:75)
[junit]     at org.hibernate.ejb.HibernatePersistence.createEntityManagerFactory(HibernatePersistence.java:54)
[junit]     at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:55)
[junit]     at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:39)
[junit]     at com.companyname.kernel.services.DBService.start(Unknown Source)
[junit]     at IntegrationUtil.Services.InitiDbservice(Unknown Source)
[junit]     at com.companyname.manage.operation.rejectinvoiceOperationTest.serviceStart(Unknown Source)

然后我做了一些阅读，发现这通常是由图书馆冲突引起的：

hibernate-commons-annotations.jar 4.0.5 
hibernate-entitymanager.jar
hibernate-c3p0.jar 4.3.8
hibernate-core.jar 4.3.8
hibernate-entitymanager.jar 4.3.8 final
hibernate-validator.jar 5.1.3 final
hibernate-jpa-2.1-api.jar 1.0.0 final
c3p0.jar 0.9.2.1

JPA信息：

<persistence-unit name="TestPU" transaction-type="RESOURCE_LOCAL">      
<properties>
<property name="hibernate.connection.url" value="jdbc:log4jdbc:sqlserver://127.0.0.1:1433;database=JPADB;" />
<property name="hibernate.connection.driver_class" value="net.sf.log4jdbc.DriverSpy" />
<property name="hibernate.dialect" value="com.companyname.kernel.persistence.jpa.UnicodeSQLServerDialect" />
<property name="hibernate.connection.autocommit" value="true" />
<property name="hibernate.show_sql" value="false" />
<property name="hibernate.hbm2ddl.auto" value="update" />


<!-- use c3p0 connection pool -->
<property name="hibernate.c3p0.min_size" value="3" />
<property name="hibernate.c3p0.max_size" value="100" />
<property name="hibernate.c3p0.timeout" value="1800" />
<property name="hibernate.c3p0.max_statements" value="0" />  
</properties>

方言代码：

registerColumnType( Types.VARBINARY, "image" );
    registerColumnType( Types.VARBINARY, 8000, "varbinary($l)" );
    registerColumnType( Types.LONGVARBINARY, "image" );
    registerColumnType( Types.LONGVARCHAR, "text" );
    registerColumnType( Types.BOOLEAN, "bit" );

新发现：我使用笔记本电脑上的eclipse连接到数据库服务器并且工作正常但是当詹金斯试图这样做时会出现上述错误。

我发现这些都没有错，但我希望你们中的一个会花时间帮我解决。欢迎任何指示。

Answer 1

我把球放在这个球上...... 好像我在更改库后没有重新编译我的数据库模块。

立即解决这个问题

JPA方言问题nosuchmethod例外

1 个答案: