Question

我想计算数组中组数组的数量。实施例

$arr1 = [61,41,41,61,89,90]
$arr2 = [61,41]
$result = 2    //found 61,41 in $arr1  2 time;

或示例

$arr1 = [89,61,41,41,61,90]
$arr2 = [61,41,89]
$result = 1    //found 61,41,89 in $arr1  1 time;

如何编写代码或概念？

Answer 1

我希望这会对你有帮助..

$arr1 = array(61,41,41,61,89,90);
$arr2 = array(61,41);

$count = array_count_values($arr1); //count values from arr1

$result = array();
foreach($arr2 as $row) {
    $result[$row] = array_key_exists($row, $count) ? $count[$row] : 0;
}

echo min($result);

$ arr2 = [61,41]输出：2

$ arr2 = [61,41,89]输出：1

Answer 2

$arr1 = array(61,41,41,61,89,90);
$arr2 = array(61,41);

$occurrences = min(
    array_count_values(array_intersect($arr1, $arr2)) + array_fill_keys($arr2, 0)
);

可以说是一个有点模糊的解决方案，但只是一个表达式。返回整个$arr2集合在$arr1中出现的数字。

在php中计算数组中组数组的数量

2 个答案: