Question

嗨我是json和php的新手，我尝试在php中循环解析json数据，但它返回空。

请帮忙。这是我的代码：

这是我的表数据

|id|data|
_________
|11|[{"id":"1","is_email":"false","add_to_day_hour_info":"false","add_to_day_hour_body":"false","translation":"Company","value":"Destination Queenstown"},{"id":"2","is_email":"false","add_to_day_hour_info":"false","add_to_day_hour_body":"false","translation":"Your Name","value":"Ella Zhang"}]|
_________
|12|[{"id":"1","is_email":"false","add_to_day_hour_info":"false","add_to_day_hour_body":"false","translation":"Company","value":"New Company"},{"id":"2","is_email":"false","add_to_day_hour_info":"false","add_to_day_hour_body":"false","translation":"Your Name","value":"Michael"}]|
_________
|13|[{"id":"1","is_email":"false","add_to_day_hour_info":"false","add_to_day_hour_body":"false","translation":"Company","value":"Blitzc inc"},{"id":"2","is_email":"false","add_to_day_hour_info":"false","add_to_day_hour_body":"false","translation":"Your Name","value":"Yudha"}]|
_________

Answer 1

您需要将第二个参数设置为true，以告诉它将结果作为关联数组返回。

$array = json_decode($array, true);

这在PHP手册中非常清楚地记录了here。

然后，您可以像这样访问value：

$array['value']

Answer 2

你的问题是table是保留的MySQL字。试试这个问题：

$sql = "SELECT id, data FROM `table`";

然后对我来说，你所有的代码都运行良好

在循环中解析json数据

2 个答案: