Question

我有一个包含SQLite数据库的应用程序。我创建了表并将值插入到表中，但是当我从表中获取数据时，它会给出错误

near "Dhanani": syntax error

这是我的获取数据方法：

-(void)getTextFromDb
{
    NSLog(@"Method Called");
    NSString *docsDir;
    NSArray *dirPaths;
    dirPaths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES);
    docsDir = dirPaths[0];

    _databasePath = [[NSString alloc]
                     initWithString: [docsDir stringByAppendingPathComponent:
                                      @"QpinData.db"]];
    const char *dbpath = [_databasePath UTF8String];
    sqlite3_stmt    *statement;
    if (sqlite3_open(dbpath, &_myDatabase) == SQLITE_OK)
    {
        NSString *querySQL = [NSString stringWithFormat:@"SELECT QpinName,Address,Lat,Long,Type FROM QPINTABLE WHERE UserName=Ramesh Dhanani"];
        const char *query_stmt = [querySQL UTF8String];

        if (sqlite3_prepare_v2(_myDatabase, query_stmt, -1, &statement, NULL) == SQLITE_OK)
        {
            [self.qpinname removeAllObjects];
            [self.qpinType removeAllObjects];
            [self.address removeAllObjects];
            [self.latitude removeAllObjects];
            [self.longitude removeAllObjects];
            while (sqlite3_step(statement) == SQLITE_ROW)
            {
                NSString *QpinName = [[NSString alloc] initWithUTF8String: (const char *) sqlite3_column_text(statement, 0)];
                NSString *Address = [[NSString alloc] initWithUTF8String: (const char *) sqlite3_column_text(statement, 1)];
                NSString *latitude = [[NSString alloc] initWithUTF8String: (const char *) sqlite3_column_text(statement, 2)];
                NSString *longitude = [[NSString alloc] initWithUTF8String: (const char *) sqlite3_column_text(statement, 3)];
                NSString *Type = [[NSString alloc] initWithUTF8String: (const char *) sqlite3_column_text(statement, 4)];
                [self.qpinname addObject:[NSString stringWithFormat:@" %@ ", QpinName]];
                [self.address addObject:[NSString stringWithFormat:@"%@ ",Address]];
                NSLog(@"self.address %@",self.address);
                [self.latitude addObject:[NSString stringWithFormat:@"%@",latitude]];
                [self.latitude addObject:[NSString stringWithFormat:@" %@",longitude]];
                [self.qpinType addObject:[NSString stringWithFormat:@" %@",Type]];
            }
            NSLog(@"%s",sqlite3_errmsg(_myDatabase));
            sqlite3_finalize(statement);
        }
        NSLog(@"%s",sqlite3_errmsg(_myDatabase));
        sqlite3_close(_myDatabase);
        [self.personalTable reloadData];
    }
}

任何帮助都将不胜感激。

Answer 1

您的SQL中有一个未引用的值。所以你要么：

在用户名值周围加上引号：

NSString *querySQL = @"SELECT QpinName,Address,Lat,Long,Type FROM QPINTABLE WHERE UserName='Ramesh Dhanani'";

如果用户名可以更改，则需要在SQL中使用?占位符，然后使用sqlite3_bind_text绑定值：

-(void)getTextFromDb
{
    NSString *docsDir = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES)[0];            
    NSString *path = [docsDir stringByAppendingPathComponent:@"QpinData.db"];
    const char *dbpath = [path UTF8String];

    sqlite3_stmt    *statement;
    if (sqlite3_open(dbpath, &_myDatabase) == SQLITE_OK) {
        const char *query_stmt = "SELECT QpinName,Address,Lat,Long,Type FROM QPINTABLE WHERE UserName=?";

        if (sqlite3_prepare_v2(_myDatabase, query_stmt, -1, &statement, NULL) == SQLITE_OK) {
            if (sqlite3_bind_text(statement, 1, [self.username UTF8String], -1, SQLITE_TRANSIENT) != SQLITE_OK) {
                NSLog(@"problem binding value: %s", sqlite3_errmsg(_myDatabase));
            }

            // clear out the model objects

            while (sqlite3_step(statement) == SQLITE_ROW) {
                NSString *qpinName = [[NSString alloc] initWithUTF8String: (const char *) sqlite3_column_text(statement, 0)];
                NSString *address = [[NSString alloc] initWithUTF8String: (const char *) sqlite3_column_text(statement, 1)];
                NSString *latitude = [[NSString alloc] initWithUTF8String: (const char *) sqlite3_column_text(statement, 2)];
                NSString *longitude = [[NSString alloc] initWithUTF8String: (const char *) sqlite3_column_text(statement, 3)];
                NSString *type = [[NSString alloc] initWithUTF8String: (const char *) sqlite3_column_text(statement, 4)];

                // populate the model objects
            }
            sqlite3_finalize(statement);
        }
        sqlite3_close(_myDatabase);
        [self.personalTable reloadData];
    }
}

Answer 2

你必须使用，
NSString *querySQL = [NSString stringWithFormat:@"SELECT QpinName,Address,Lat,Long,Type FROM QPINTABLE WHERE UserName='Ramesh Dhanani'"];

因为查询中的任何字符串都必须是单引号。

为什么报告SQLite语法错误

2 个答案: