Question

我有以下内容：

public class CustomObject{
   public String name = "John";
   public int age = 14;
}

我有多个CustomObject存储在这个变量的地图中：

Map<Long, CustomObject> myCustomObjectsMap;

有没有办法让我有两个方法，一个将这个地图转换成一个字节数组，另一个只读取bytearray并将其转换回Map myCustomObjectsMap？

Answer 1

是的，你可以。

这是怎么回事？

public class ConvertMapToBytes {

    public static void main(String[] args) {
        Map<Long, CustomObject> map = new HashMap<Long, CustomObject>();

        CustomObject c = new CustomObject();
        c.age = 20;
        c.name = "name";

        CustomObject c2 = new CustomObject();

        map.put(1L, c);
        map.put(2L, c2);

        try {
            byte[] bytes = convertMap(map);

            System.out.println("got bytes");

            // deserialise
            Map<Long, CustomObject> map2 = convertBytes(bytes);
            for (CustomObject co : map2.values()) {
                System.out.println(co);
            }
        } catch (Exception e) {
            e.printStackTrace();
        }

    }

    public static byte[] convertMap(Map<Long, CustomObject> map) throws Exception {
        ByteArrayOutputStream baos = new ByteArrayOutputStream();
        new ObjectOutputStream(baos).writeObject(map);
        return baos.toByteArray();
    }

    @SuppressWarnings("unchecked")
    public static Map<Long, CustomObject> convertBytes(byte[] obj) throws Exception {
        return (Map<Long, CustomObject>)new ObjectInputStream(new ByteArrayInputStream(obj)).readObject();
    }

}

class CustomObject implements Serializable {
    private static final long serialVersionUID = 1L;

    public String name = "John";
    public int age = 14;

    @Override
    public String toString() {
        return "name: " + name + ", age: " + age;
    }
}

你能将Java Map <long，customobject>转换为byte []然后转换回Map <long，customobject>吗？</long，customobject> </long，customobject>

1 个答案: