Question

因此，在我的java书介绍中，我的任务是：

假设今年大学的学费为10,000美元，每年增加5％。在一年内，学费将为10,500美元。写一个计算十年学费的计划和十年后四年学费的总费用。

我可以很容易地计算出第十年的学费，但令我难过的是如何在11年，12年级，13年级和14年级添加独特的学费值。如果我是对的，它应该加起来为73717.764259。我的代码给我的是158394.52795515177。正如代码所说的那样，我可能只是以错误的方式思考这个问题，并且我的代码正确地进行了添加，但我认为我更适合这里。这是我现在使用的代码：

    double initialTuition = 10000;
    final double theRate = 0.05;

    for (int i = 1; i < 15; i++) {
        initialTuition = ((theRate * initialTuition) + initialTuition);
        System.out.println("Year " + i + " tuition is: " + initialTuition);
        while (i == 10){
            System.out.println("Year " + i + " tuition is: " + initialTuition);
            double startOfFourYearTuition = initialTuition;
            System.out.println(startOfFourYearTuition);
            break;
        }

        while ((i > 10) && (i < 15)) {
            System.out.println("Year " + i + " tuition is: " + initialTuition);
            initialTuition += initialTuition;
            break;
        }

    }

最后一次循环是我尝试添加4年。

重申一个问题，如何在迭代11到14中提取initialTuition的唯一值并添加它们？

Answer 1

你也有很多无偿的代码，而for循环内部的循环等等。试试这个大小：

public static void main(String[] args) 
{
    double initialTuition = 10000;
    double summarizedTuition = 0;

    final double theRate = 0.05;

    for (int i = 1; i < 15; i++) {
        initialTuition = ((theRate * initialTuition) + initialTuition);
        System.out.println("Year " + i + " tuition is: " + initialTuition);

        if ((i > 10) && (i < 15)) 
        {
            summarizedTuition += initialTuition;
        }
    }

    System.out.println("Summarized tuition for years 11 - 14: " + summarizedTuition);
}

输出结果为：

Year 1 tuition is: 10500.0
Year 2 tuition is: 11025.0
Year 3 tuition is: 11576.25
Year 4 tuition is: 12155.0625
Year 5 tuition is: 12762.815625
Year 6 tuition is: 13400.95640625
Year 7 tuition is: 14071.0042265625
Year 8 tuition is: 14774.554437890625
Year 9 tuition is: 15513.282159785156
Year 10 tuition is: 16288.946267774414
Year 11 tuition is: 17103.393581163135
Year 12 tuition is: 17958.56326022129
Year 13 tuition is: 18856.491423232354
Year 14 tuition is: 19799.31599439397
Summarized tuition for years 11 - 14: 73717.76425901074

Answer 2

        double theRate = 1.05; // rate of increase +5%
        double tuitionCost = 10000; // base cost
        double fourYearCost = 0; // four year cost (years 10-13)
        for (int i = 0; i <= 13; i++) {
            System.out.println("Cost of year: " + i + " is $" + tuitionCost); // print out this years cost
            if(i >= 10){ //if its year 10, 11, 12, 13
                fourYearCost += tuitionCost; // add this years tuition cost
            }
            tuitionCost *= theRate; // increment the tuition (mutiply it by 1.05, or 5% increase)
        }

        System.out.println("Cost of tuition for years 10, 11, 12, 13: $" + fourYearCost); // print the cost for the remaining years

如何在独特的迭代中从循环中提取值？

2 个答案: