这是我的示例代码:
function out(msg)
{
$('#output').append(msg + '<br>');
}
var myDeferred = [];
$.each([8, 3, 4, 6, 9, 15, 7, 1], function (index, time)
{
myDeferred.push($.Deferred(function(dfd)
{
setTimeout(function ()
{
out(time);
dfd.resolve();
}, time * 1000);
}).promise());
});
$.when.apply($, myDeferred).then(function ()
{
out('all is done');
});
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="output"></div>
&#13;
此输出&#34; 1 3 4 6 7 8 9 15全部完成&#34; ,同时调用所有回调。
有人可以帮助我吗?
提前致谢
答案 0 :(得分:3)
问题是每个回调超时几乎同时被激活。您可以执行以下操作:
function out(msg)
{
$('#output').append(msg + '<br>');
}
function foo(index, callback) {
var time = array[index];
out(time);
if (index == array.length - 1)
callback();
else
setTimeout(foo, time * 1000, index + 1, callback);
}
var array = [8, 3, 4, 6, 9, 15, 7, 1];
foo(0, function ()
{
out('all is done');
});
使用承诺:
function out(msg)
{
$('#output').append(msg + '<br>');
}
var myDeferred = [];
$.each([8, 3, 4, 6, 9, 15, 7, 1], function (index, time)
{
myDeferred.push($.Deferred(function(dfd)
{
var f = function() {
out(time);
dfd.resolve();
}
if (index > 0)
myDeferred[index - 1].done(function() { setTimeout(f, time * 1000); });
else
setTimeout(f, time * 1000);
}).promise());
});
$.when.apply($, myDeferred).then(function ()
{
out('all is done');
});
答案 1 :(得分:2)
不是在初始循环中记录您的回复,而是将数据传递到resolve()
,然后在when()
内,您将收到已解析数据的数组。改为循环遍历该数组,所有都将按顺序
var myDeferred = [];
$.each([8, 3, 4, 6, 9, 15, 7, 1], function (index, time)
{
myDeferred.push($.Deferred(function(dfd)
{
setTimeout(function ()
{
/* pass data to resolve()*/
dfd.resolve(time);
}, time * 100);
}).promise());
});
$.when.apply($, myDeferred).then(function ()
{
/* loop over arguments */
$.each(arguments,function(_, time){
out(time);
});
console.log(arguments);
out('all is done');
});
的 DEMO 强>