我在DB中有2个参数：启动和停止。它们的价值可以是例如07：00-23：00或23：00-07：00 （07后开始，23后停止或23后开始，07后停止）
在那个时候，状态必须是0或1，让我们说它是LED
如何创建在午夜之后/之前不会弄乱的统一逻辑控制器？
我的糟糕实施（不会工作）如下。实际上，我尝试了许多变化，但最终仍然是我现在所处的位置。
if curtime >= vv_time_trig1 and curtime <= vv_time_trig2:
logger.info("turning socket on")
logger.debug("#1")
#check current status
#if current is 0
#turn socket on
if vvstatus == 0:
logger.debug("current status off, turning socket on")
GPIO.output(25, GPIO.HIGH)
#check current status
#if current is already 1
#do nothing
elif vvstatus == 1:
logger.info("skiping. already on")
#unhandeled current status
else:
logger.critical("unhandeled vvstatus!")
logger.critical("turning socket off")
GPIO.output(25, GPIO.LOW)
#if current time is before start
#turn off
elif curtime <= vv_time_trig1 and curtime >= vv_time_trig2:
logger.info("turning socket off")
logger.debug("#2")
#check current status
#if current is 1
#turn socket off
if vvstatus == 1:
logger.debug("current status on, turning socket off")
GPIO.output(25, GPIO.LOW)
#check current status
#if current is already 0
#do nothing
elif vvstatus == 0:
logger.info("skiping. already off")
#unhandeled current status
else:
logger.critical("unhandeled vvstatus!")
logger.critical("turning socket off")
GPIO.output(25, GPIO.LOW)
#if current time is after stop
#turn off
elif curtime >= vv_time_trig2:
logger.info("turning socket off")
logger.debug("#3")
#check current status
#if current is 1
#turn socket off
if vvstatus == 1:
logger.debug("current status: %s, turning socket off", vvstatus)
GPIO.output(25, GPIO.LOW)
#check current status
#if current is already 0
#do nothing
elif vvstatus == 0:
logger.info("skiping. already on")
#unhandeled current status
else:
logger.critical("unhandeled vvstatus!")
logger.critical("turning socket off")
GPIO.output(25, GPIO.LOW)
#if current time is before stop
#turn off
elif curtime <= vv_time_trig2 and curtime <= vv_time_trig1:
logger.info("turning socket on")
logger.debug("#4")
#check current status
#if current is 0
#turn socket on
if vvstatus == 0:
logger.debug("current status off, turning socket on")
GPIO.output(25, GPIO.HIGH)
#check current status
#if current is already 1
#do nothing
elif vvstatus == 1:
logger.info("skiping. already on")
#unhandeled current status
else:
logger.critical("unhandeled vvstatus!")
logger.critical("turning socket off")
GPIO.output(25, GPIO.LOW)
更新版本。 确定相对于结束的当前时间位置。如果午夜过去，结束将设置为明天
n1 = datetime.now()
startTrig = datetime(n1.year, n1.month, n1.day, 23, 00, 0)
logger.debug("start: %s",startTrig)
n = datetime.now()
endTrig = datetime(n.year, n.month, n.day, 07, 00, 0)
logger.debug("end: %s",endTrig)
if startTrig > endTrig:
logger.debug("start > stop")
endTrig += timedelta(days=1)
logger.debug("new stop trig: %s",endTrig)
if datetime.now() < endTrig:
if curStatus == 1:
logger.debug("socket %s already on. doing nothing.")
elif curStatus == 0:
logger.debug("socket %s sould be on. flipping switch")
flipSocketStatus(bcmNo,bcmDir)
else:
logger.critical("unhandeled socket %s current status %s",socName,curStatus)
if curStatus == 1:
logger.critical("shutting socket %s down",socName)
GPIO.output(bcmNo, GPIO.LOW)
elif curStatus == 0:
logger.warn("socket %s already off",socName)
else:
logger.critical("unhandeled current status for pin: %s",bcmNo)
logger.critical("forcing socket %s down",socName)
GPIO.output(bcmNo, GPIO.LOW)
else:
logger.critical("unhandeled start-stop rules")
答案 0 :(得分：1)
更新：根据您的更新
这看起来更好，我唯一困惑的是你的if datetime.now() < endTrig条件。
如果我仍然误解你，请纠正我，但你现在的条件似乎如下：
if now() is before endTrigger:
- if status is 1, we are good, stay on
- if status is 0, turn on
- if status is anything else (but cant it only be 1 or 0?):
* if status is 1 ... (but wait, we already checked for this above!)
* if status is 0 ... (ditto, these two checks will never trigger)
* otherwise, force off
if now() is after endTime:
- some logging (shouldnt this be where we turn off?)
你提到的状态必须是0或1.基于此，我希望你的条件看起来像：
.
. [start/end setup stuff]
.
# If we haven't reached end time yet
if datetime.now() < endTrig:
# If status is 1, we're already on
if curStatus == 1:
log('Already on')
# If status isn't 1, it must be 0 and we should turn on
else:
log('Turn on')
flipSwitchOn()
# If we have passed the end time
else:
# If we're on, time to turn off
if curStatus == 1:
log('Turning off')
flipSwitchOff()
# If its not 1 it must be 0, we're off, stay off
else:
log('Already off')
答案 1 :(得分：1)
有两种情况：当前时间介于给定时间（顺时针）或外部（想象时钟圈）：
#!/usr/bin/env python
from datetime import datetime
def in_between(now, start, end):
if start < end: # e.g., "07:00-23:00"
return start <= now < end
elif end < start: # e.g., "23:00-07:00"
return start <= now or now < end
else: # start == end
return True # consider it 24 hour interval
now = datetime.now().time()
for date_range in ["07:00-23:00", "23:00-07:00"]:
start, end = [datetime.strptime(s, "%H:%M").time()
for s in date_range.split("-")]
not_ = '' if in_between(now, start, end) else 'not '
print("{now:%H:%M} is {not_}in between {date_range}".format(**vars()))
02:26 is not in between 07:00-23:00
02:26 is in between 23:00-07:00