我有一段代码,我声明了默认构造函数和参数构造函数。
Student_APP Secondstudent = new Student_APP("2345");
Secondstudent.score1 = 30;
Secondstudent.score2 = 20;
Secondstudent.score3 = 10;
Console.WriteLine("Student Number: " + Secondstudent.studentNumber + "\nAverage: {0:F1}",
Secondstudent.CalculateAverage());
Student_APP Thirdstudent = new Student_APP("5432", "xyz", "zxy");
Thirdstudent.major = "Maths";
Thirdstudent.score1 = 97;
Thirdstudent.score2 = 56;
Thirdstudent.score3 = 76;
Console.WriteLine("\n\n Third student ");
Console.WriteLine(Thirdstudent);
Student_APP LastStudent = new Student_APP("2255", "yxx", "xyy",94,54,74,"CS");
//LastStudent.major = "CS";
//LastStudent.score1 = 94;
//LastStudent.score2 = 54;
//LastStudent.score3 = 74;
我这里没有使用过这个关键字,但是我得到了像
这样的编译错误错误4'StudentAppWithoutgetset.Student_APP'不包含 带有7个参数的构造函数C:\ Users \ hariharan.v \ Desktop \ Office Training \ MyfirstProgCarpet \ StudentApp \ StudentAppWithoutgetset \ StudentAppWithoutgetset \ Program.cs 47 39 StudentAppWithoutgetset
请帮帮我。
答案 0 :(得分:1)
你有一个带7个参数的构造函数吗? 尝试添加:
public Student_APP(string p1, string p2, string p3, int p4, int p5, int p6, string p7)
{
//...
}
答案 1 :(得分:1)
与此关键字无关的问题,但它与自己的构造函数有关。 在你的类中,没有构造函数可以使用7个参数,因此在将它用于对象之前,应该在类中编写它。
public Student_APP(string p1, string p2, string p3, int p4, int p5, int p6, string p7)
{
//...
}
答案 2 :(得分:0)
如果我理解正确,每次你做一个新的,例如
Student_APP LastStudent = new Student_APP("2255", "yxx", "xyy",94,54,74,"CS");
您正在实例化Student_APP
的对象。您在括号("2255", "yxx", "xyy",94,54,74,"CS")
中传递的参数和错误消息似乎表明您需要Student_APP
的构造函数,该构造函数包含7个参数。
所以在课堂Student_APP
中你需要:
public Student_APP(string firstParam, string secondParam, string thirdParam, int fourthParam, int fifthParam, int sixthParam, string seventhParam)
{
_firstParam = firstParam;
_secondParam = secondParam;
//....
_seventhParam = seventhParam;
}
您能否举例说明'this'的含义,以便我们更清晰地解决问题。我认为这是误解的根源。
答案 3 :(得分:0)
假设您的Student_APP类是这样的
public class Student_APP
{
// Public properties with get/set and an automatic backing field
public int score1 {get; set;}
public int score2 {get; set;}
public int score3 {get; set;}
public string major {get; set;}
// Internal properties
private int _id;
private string _surname;
private string _name;
public Student()
{}
public Student(int idnumber)
{
_id = idnumber;
}
public Student(int idnumber, string surname, string name)
{
_id = idnumber;
_surname = surname;
_name = name;
}
}
现在,您可以使用Object and Collection Initializer syntax
声明并初始化此类的实例Student_APP s = new Student_APP(2255, "xyz", "xyz") {score1 = 94, score2=54, score3=74, major = "CS"};
当然,如果您的目的是消除Student_APP
类的公共属性,那么您需要添加一个带有7个参数的appropriace构造函数,如其他答案中所述。
在上面的示例中,Student_APP
类有三个构造函数,但它们都没有代码所需的7个参数签名,因此您得到了上述错误。