代码 -
"use strict";
var AJAX = function (params) {
this.server ={};
this.url = params.url;
this.method = params.method;
this.dataType = params.dataType;
this.formData = params.formData;
this.init = function(){
if(typeof XMLHttpRequest != 'undefined'){
this.server = new XMLHttpRequest();
this.server.setRequestHeader('Content-type', 'application/x-www-form-urlencoded');
this.server.setRequestHeader('Content-length', this.formData.length);
this.server.setRequestHeader('Connection', 'close');
console.log("XMLHttpRequest created.");
return true;
}
};
this.send = function(){
if(this.init()){
this.server.open(this.method, this.url, true);
this.server.send(this.formData);
}
};
};
抛出以下错误:
Error in event handler for contextMenus: InvalidStateError: Failed to execute 'setRequestHeader' on 'XMLHttpRequest': The object's state must be OPENED.
如何使用
var data = new FormData();
data.append('user', 'sachin');
var params = {
url : 'example.com',
method : 'post',
dataType: 'json',
formData : data
};
var backgroundWindow = chrome.extension.getBackgroundPage();
var ajax = new backgroundWindow.AJAX(params);
ajax.send();
我似乎无法弄清楚背后的原因是什么。
答案 0 :(得分:39)
错误很简单:
contextMenus的事件处理程序出错:InvalidStateError:无法执行' setRequestHeader' on' XMLHttpRequest':对象的状态必须打开。
您需要在设置请求标头之前调用.open(..)
。
鉴于您的代码,我认为最好的方法是将调用移至init(..)
函数中打开。
var AJAX = function (params) {
this.server ={};
this.url = params.url;
this.method = params.method;
this.dataType = params.dataType;
this.formData = params.formData;
this.init = function(){
if(typeof XMLHttpRequest != 'undefined'){
this.server = new XMLHttpRequest();
//Open first, before setting the request headers.
this.server.open(this.method, this.url, true);
//Now set the request headers.
this.server.setRequestHeader('Content-type', 'application/x-www-form-urlencoded');
//this.server.setRequestHeader('Content-length', this.formData.length);
//this.server.setRequestHeader('Connection', 'close');
console.log("XMLHttpRequest created.");
return true;
}
};
this.send = function(){
if(this.init()){
this.server.send(this.formData);
}
};
};
答案 1 :(得分:3)
您可能需要在XMLHttpRequest
来电之后和setRequestHeader
来电之前打开连接而不是:
this.server = new XMLHttpRequest();
this.server.setRequestHeader('Content-type', 'application/x-www-form-urlencoded');
我认为你需要这样做:
this.server = new XMLHttpRequest();
this.server.open(this.method, this.url, true);
this.server.setRequestHeader('Content-type', 'application/x-www-form-urlencoded');
还要确保在init()
中删除此行,就像您上面所做的那样。