所以我是Java的初学者,我的教授让我们做这个任务,我一直在四处寻找,但我似乎无法找到适合我的代码类型的答案。我们必须创建一个类文件,然后创建一个公共类文件来测试它。
import java.io.Serializable;
public class Person implements Serializable {
String Fname = new String();
String MI = new String();
String Lname = new String();
String age = new String();
String gpa = new String();
// int age = 20;
// double gpa = 0.0;
String Major = new String();
String answer;
//***********************************************
// The methods declared will go below
// The first method is for the first name
public String getFname() {
return Fname;
}
public void setFname(String Fname) {
this.Fname = Fname;
}
// This method is for the Middle Initial
public String getMI() {
return MI;
}
public void setMI(String MI) {
this.MI = MI;
}
// This method is for the Last name
public String getLname() {
return Lname;
}
public void setLname(String Lname) {
this.Lname = Lname;
}
// This method is for the Age
public String getAge() {
return age;
}
public void setAge(String age) {
this.age = age;
}
// This method is for the GPA
public String getGpa() {
return gpa;
}
public void setGpa(String gpa) {
this.gpa = gpa;
}
// This method is for the Major
public String getMajor() {
return Major;
}
public void setMajor(String Major) {
this.Major = Major;
}
}
Person.java代码是Serializable,应该写入fhm文件,然后反序列化,以便将文件内容打印到终端(Unix)。下面是主要代码,它是TestPerson代码,它将读取类Person代码。
import java.util.Scanner;
import java.io.*;
public class TestPerson {
public static void main(String[] args) throws IOException, ClassNotFoundException {
Person[] Peeps = new Person[3];
Peeps[0] = new Person();
Peeps[1] = new Person();
Peeps[2] = new Person();
Scanner scan = new Scanner(System.in);
String Answer = new String();
String age1 = new String();
String gpa1 = new String();
for (int i = 0; i < Peeps.length - 1; i++) {
// for (int i = 0; i < 3; i++) {
System.out.print("What is the First Name? ");
Answer = scan.nextLine();
Peeps[i].setFname(Answer);
System.out.print("What is MI? ");
Answer = scan.nextLine();
Peeps[i].setMI(Answer);
System.out.print(" What is Last Name? ");
Answer = scan.nextLine();
Peeps[i].setLname(Answer);
System.out.print(" What is the Age? ");
age1 = scan.nextLine();
int age = Integer.parseInt(age1);
// age = scan.nextInt();
Peeps[i].setAge(age1);
System.out.print(" What is the GPA? ");
gpa1 = scan.nextLine();
double gpa = Double.parseDouble(gpa1);
Peeps[i].setGpa(gpa1);
System.out.print(" What is the Major? ");
Answer = scan.nextLine();
Peeps[i].setMajor(Answer);
}
for (int i = 0; i < 3; i++) {
System.out.print(Peeps[i]);
}
try {
FileOutputStream fileOut = new FileOutputStream("Peeps.fhm");
ObjectOutputStream out = new ObjectOutputStream(fileOut);
out.writeObject(Peeps);
out.close();
fileOut.close();
System.out.println("\nSerialization Successful\n");
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
try {
FileInputStream fileIn = new FileInputStream("Peeps.fhm");
ObjectInputStream in = new ObjectInputStream(fileIn);
System.out.println("Deserialized Data: \n" + in.readObject().toString());
in.close();
fileIn.close();
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
}
我的教授希望我提示用户输入终端中两个Person对象的数据,然后将引用复制到两个填充的人之一到最后一个Person。然后程序将所有三个人写入磁盘文件,扩展名为&#34; .fhm&#34; (我已经完成了)。我的问题是如何复制参考?我的第二个问题也是如何正确反序列化文件,因为当我运行它时,它可以工作,但弹出的问题是它告诉我这个:
Deserialized Data: [LPerson;@5e481248
他希望它能够打印用户输入的信息。我检查了它写入的fhm文件,它收集了所有信息,因此我不确定我做错了什么。任何帮助将不胜感激的家伙,抱歉这篇文章有点长。提前致谢。
答案 0 :(得分:1)
您的对象基本上是一个Java数组。要打印出来,您可以使用:
System.out.println("Deserialized Data: \n" + Arrays.toString(in.readObject()));
答案 1 :(得分:1)
我不确定你的意思是什么?复制参考&#34;一部分。
反序列化似乎运作良好。
但是在您的代码中,您实际上只是调用.toString()
来打印数组,这可能不是您想要的。
您可能希望迭代这些项目并逐个打印:
FileInputStream fileIn = new FileInputStream("Peeps.fhm");
ObjectInputStream in = new ObjectInputStream(fileIn);
Person[] peeps = in.readObject();
System.out.println("Deserialized Data:");
for (Person person : peeps) {
System.out.printf("First Name: %s MI: %s Last Name: %s%n",
person.getFname(), person.getMI(), person.getLname());
}