Question

我一直试图让我的对话只能由发送者和接收者查看。任何帮助或方向指示将不胜感激。

对话控制器

class ConversationsController < ApplicationController
  def index

   @conversations = Conversation.all
   #@conversation = current_user.conversation.from_id + @user.conversation.to_id
   #@conversations = current_user.messages.find(params[:id])
   #@conversations = current_user && @user != current_user
   #@conversations = Conversation.find(current_user).last
   #@conversations = from.id + to.id
  end

会话模型

class Conversation < ActiveRecord::Base

 validates :to_id, :from_id, presence: true

 belongs_to :to, class_name: "User"
 belongs_to :from, class_name: "User"
 has_many :messages, dependent: :destroy, inverse_of: :conversation

 def self.exist_with?(user, current_user)
  if Conversation.where(from_id: user.id ,to_id: current_user.id).blank? &&
     Conversation.where(from_id: current_user.id, to_id: user.id).blank?
     return false   
  else
    return true
  end
 end

 def self.find_conversation(user, current_user)
  conversation = Conversation.where(from_id: user.id ,to_id: current_user.id) +
                 Conversation.where(from_id: current_user.id, to_id: user.id)
  conversation.first
 end
end

对话Index.html.erb

<h1 class="message"> Messages </h1>

<ul>
 <% @conversations.reverse.each do |conversation| %>
  <li class="cmessages"> 
   <%= image_tag conversation.to.avatar.url(:thumb), :class => "username-picture" %>
   <%= link_to conversation.to.user_name, "/conversations/#{ conversation.id }", :class => "username" %>
   <%= time_ago_in_words(conversation.created_at) %> ago
  </li>
<% end %>

对话架构

create_table "conversations", force: true do |t|
 t.integer  "to_id"
 t.integer  "from_id"
 t.datetime "created_at"
 t.datetime "updated_at"
 t.integer  "user_id"
end

如果缺少某些内容，请通知我，我将包含可能缺少的任何文件信息以解决此问题。再次感谢大家的帮助，并为我的问题指出正确的方向。祝你有美好的一天。

Answer 1

class ConversationsController < ApplicationController
  def index
    @conversations = Conversation.where("from_id = :user OR to_id = :user", user: current_user.id)
  end

为避免将模型逻辑填充到控制器中，请在模型中创建方法或范围

class Conversation < ActiveRecord::Base
  def self.accessible_by(user)
    where("from_id = :user OR to_id = :user", user: user.id)
  end
end

并在控制器中重复使用

class ConversationsController < ApplicationController
  def index
    @conversations = Conversation.accessible_by(current_user)
  end

还要注意以下查询

where("from_id = :user OR to_id = :user", user: user.id)

这只是

的捷径

where("from_id = ? OR to_id = ?", user.id, user.id)

使对话仅对from_id和to_id可见

1 个答案: