Question

我试图在没有xml配置的情况下运行基本的spring-4 web-mvc应用程序。我看过弹簧文档和示例，但它对我没用。我的控制器：

package com.nikolay.exam.controller;

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.ResponseBody;
@Controller
public class HomeController {

@RequestMapping(value = "/home", method = RequestMethod.GET)
@ResponseBody
public String home() {
    return "Hello world!";
}
}

的AppConfig：

package com.nikolay.exam.config;

import org.springframework.context.annotation.Configuration;

@Configuration
    public class AppConfig {
}

WebConfig：

package com.nikolay.exam.config;
import com.nikolay.exam.controller.HomeController;
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.Configuration;
import org.springframework.web.servlet.config.annotation.EnableWebMvc;
import org.springframework.web.servlet.config.annotation.WebMvcConfigurerAdapter;
@Configuration
@EnableWebMvc
public class WebConfig extends WebMvcConfigurerAdapter {

@Bean
public HomeController homeController() {
        return new HomeController();
    }
}

WebInitializer：

package com.nikolay.exam.config;

import org.springframework.web.WebApplicationInitializer;
import org.springframework.web.context.ContextLoaderListener;
import org.springframework.web.context.support.AnnotationConfigWebApplicationContext;
import org.springframework.web.servlet.DispatcherServlet;

import javax.servlet.ServletContext;
import javax.servlet.ServletException;
import javax.servlet.ServletRegistration;
public class WebInitializer implements WebApplicationInitializer {
    @Override
    public void onStartup(ServletContext servletContext) throws ServletException {
        AnnotationConfigWebApplicationContext root = new AnnotationConfigWebApplicationContext();
        root.setConfigLocation("com.nikolay.exam.config");

        servletContext.addListener(new ContextLoaderListener(root));
        ServletRegistration.Dynamic dispatcher = servletContext.addServlet("dispatcher", new DispatcherServlet(root));
        dispatcher.setLoadOnStartup(1);
        dispatcher.addMapping("/*");

    }
}

但是当我在tomcat上运行我的应用程序时，我收到一个错误：

14-Feb-2015 11：35：29.825警告[http-nio-8080-exec-1] org.springframework.web.servlet.PageNotFound.noHandlerFound找不到带有URI [/ home /]的HTTP请求的映射DispatcherServlet，名称为＆＃39; dispatcher＆＃39; 14-Feb-2015 11：35：32.766 INFO [localhost-startStop-1] org.apache.catalina.startup.HostConfig.deployDirectory部署Web应用程序目录/home/nikolay/apache-tomcat-8.0.9/webapps/manager 14-Feb-2015 11：35：32.904 INFO [localhost-startStop-1] org.apache.catalina.startup.HostConfig.deployDirectory部署Web应用程序目录/home/nikolay/apache-tomcat-8.0.9/webapps/manager已完成136毫秒 14-Feb-2015 11：35：34.888警告[http-nio-8080-exec-3] org.springframework.web.servlet.PageNotFound.noHandlerFound在DispatcherServlet中找不到带有URI [/ home /]的HTTP请求的映射名称＆＃39;调度＆＃39;

Answer 1

我认为这是注册配置类的方式不正确。

请尝试使用AnnotationConfigWebApplicationContext#register。

AnnotationConfigWebApplicationContext appContext = new AnnotationConfigWebApplicationContext();
appContext.register(WebConfig.class);

Answer 2

可能你需要改变

dispatcher.addMapping("/*");

到

dispatcher.addMapping("/");

spring web-mvc 4 java config不起作用

2 个答案: