Question

我使用JSON Schema Validator（https://github.com/fge/json-schema-validator）来验证这个简单对象的内容：

{
  "firstName": "Bob",
  "lastName": "Smith",
  "age": 23
}

我的架构由以下人员定义：

{
  "$schema": "http://json-schema.org/draft-04/schema#",
  "type": "object",
  "properties": {
    "firstName": {
      "type": "string"
      },
      "lastName": {
      "type": "string"
      },
      "age": {
         "type": "integer"
      }
     }, 
     "required": ["firstName", "lastName", "age"]
}

我编写了以下代码来使用模式验证对象：

   public static void main(String[] args) throws IOException {      
    ObjectMapper mapper = new ObjectMapper();

    // Create the source configuration file
    ObjectNode sourceConfig = mapper.createObjectNode();
    sourceConfig.put("firstName", "Bob");
    sourceConfig.put("lastName", "Smith");
    sourceConfig.put("age", 23);

    // Create the schema used for validation
    ObjectNode schema = mapper.createObjectNode();
    schema.put("$schema", "http://json-schema.org/draft-04/schema#");
    schema.put("type", "object"); 

    ObjectNode properties = mapper.createObjectNode();

    ObjectNode firstName = mapper.createObjectNode();
    firstName.put("type", "string");
    properties.put("firstName", firstName);

    ObjectNode lastName = mapper.createObjectNode();
    lastName.put("type", "string");
    properties.put("lastName", lastName);

    ObjectNode age = mapper.createObjectNode();
    age.put("type", "integer");
    properties.put("age", age);

    List<String> required = new ArrayList<String>();
    required.add("firstName");
    required.add("lastName");
    required.add("age");

    // Convert the list to an arraynode and add to schema
    ArrayNode array = mapper.valueToTree(required);
    schema.putArray("required").addAll(array);
    schema.put("properties", properties);

    JsonSchemaFactory factory = JsonSchemaFactory.byDefault();
    JsonSchema schemaValidation = null;

    try {
         schemaValidation = factory.getJsonSchema(schema);
    }

    catch (ProcessingException e) {
        e.printStackTrace();
    }

    ProcessingReport report = null;

    try {
        report = schemaValidation.validate(sourceConfig);
    } 

    catch (ProcessingException e) {
        e.printStackTrace();
    }
}

这是我运行程序时出现的错误：

Exception in thread "main" java.lang.NoSuchFieldError: WRITE_BIGDECIMAL_AS_PLAIN
    at com.github.fge.jackson.JacksonUtils.newMapper(JacksonUtils.java:155)
    at com.github.fge.jackson.JacksonUtils.<clinit>(JacksonUtils.java:55)
    at com.github.fge.jackson.JsonNodeReader.<init>(JsonNodeReader.java:82)
    at com.github.fge.jackson.JsonLoader.<clinit>(JsonLoader.java:50)
    at com.github.fge.jsonschema.SchemaVersion.<init>(SchemaVersion.java:63)
    at com.github.fge.jsonschema.SchemaVersion.<clinit>(SchemaVersion.java:44)
    at com.github.fge.jsonschema.core.load.configuration.LoadingConfigurationBuilder.<init>(LoadingConfigurationBuilder.java:117)
    at com.github.fge.jsonschema.core.load.configuration.LoadingConfiguration.byDefault(LoadingConfiguration.java:151)
    at com.github.fge.jsonschema.main.JsonSchemaFactoryBuilder.<init>(JsonSchemaFactoryBuilder.java:67)
    at com.github.fge.jsonschema.main.JsonSchemaFactory.newBuilder(JsonSchemaFactory.java:123)
    at com.github.fge.jsonschema.main.JsonSchemaFactory.byDefault(JsonSchemaFactory.java:113)
    at PlayingWithJsonSchemaValidation.main(PlayingWithJsonSchemaValidation.java:114)

当我通过调试器运行程序时，JsonSchemaFactory factory = JsonSchemaFactory.byDefault（）;我不确定如何修复此错误，或者代码究竟出了什么问题。有人可以给我一些解决方法吗？

无法使用JSON Schema Validator验证架构，JsonSchemaFactory.byDefault（）会发生错误;

0 个答案: