Question

我写了一个简单的骰子游戏，除了我正在努力的部分之外，按预期工作，这是如何用按下的特定键结束游戏。我知道我做的是一个简单的错误（我是初学者），但是如果你能指出代码有什么问题，我会很高兴的。

谢谢！

import random



def game():
    while True:

        userRoll = int(raw_input("Enter a number from 1 to 10 [press q to end the game]: "))
        compRoll = random.randrange(1, 11)

        print "You rolled " + str(userRoll) 
        print "Computer rolled " + str(compRoll)

        if userRoll > compRoll and userRoll > 0 and userRoll < 11:
            print "You win!"

        elif userRoll == compRoll:
            print "It's a tie!"

        elif userRoll < compRoll:
            print "Computer wins!"

        elif userRoll == 'q':
            print "bye"
            break

        else:
            print "You must enter number from 1 to 10. Try again..."

game()

Answer 1

此代码无效：

    elif userRoll == 'q':
        print "bye"
        break

到该代码执行时，您已将userRoll转换为整数。所以，如果永远不能通过q。以下代码在转换为整数之前测试userRoll == 'q'：

import random

def game():
    while True:

        userRoll = raw_input("Enter a number from 1 to 10 [press q to end the game]: ")
        if userRoll == 'q':
            print "bye"
            break
        userRoll = int(userRoll)

        compRoll = random.randrange(1, 11)

        print "You rolled " + str(userRoll)_
        print "Computer rolled " + str(compRoll)

        if userRoll > compRoll and userRoll > 0 and userRoll < 11:
            print "You win!"

        elif userRoll == compRoll:
            print "It's a tie!"

        elif userRoll < compRoll:
            print "Computer wins!"

        else:
            print "You must enter number from 1 to 10. Try again..."

game()

从while循环中断

1 个答案: