如果datetime字段的值为nil
,我正在尝试更改单元格的值但它会不断将值更改为今日日期
-elsif k=='pickup' || k=='delivery' || k=='Posted On'
- if v.nil?
= "Unknown"
- else
= v.strftime("%D")
Load.find(load_id).delivery.nil?
=> true
Load.find(load_id)
=> #<Load id: 904237, length: 53, delivery: nil, pickup: "2014-09-09 17:00:00", weight: nil, equipment_id: 26, covered: false, created_at: "2014-08-18 13:21:25", updated_at: "2014-11-24 21:55:03">
实际上我已经进一步缩小范围猜猜它不在我看来......
但实际上当我从我的控制器中的数据库中提取它时...它将@load设置为默认传递值
显示控制器:
def show
if params[:load]
params[:load].delete(:type)
params[:load][:origin] = Location.to_point(params[:load][:origin])
params[:load][:dest] = Location.to_point(params[:load][:dest])
@load = Load.new(params[:load])
@load.updated_at = Time.now
flash.keep[:notice] = 'Please be aware that it could take up to 5 minutes for your load to appear in search results.'
else
@load = Load.find(params[:id])
current_location(@load)
@return_hotloads = Hotload.return_hotloads(@load)
@return_loads = Load.return_loads(@load)
end
authorize! :show, @load
end
交货应该是零
@load
=>
#<Load id: 904237, user_id: 10640, delivery: "2015-02-13 21:48:21", pickup: "2014-09-09 17:00:00", weight: nil, tracking: nil>
但如果我在视图中执行此操作,它会显示为我想要的空白:
-elsif k=='delivery'
- l = Load.find(@load.id).delivery
- if l
= l.strftime("%D")
女巫真的很奇怪....