我有像
这样的Spring RESTful服务 @RequestMapping(value = "/test", method = RequestMethod.POST, headers = { "content-type=application/xml" })
@Transactional(readOnly = false)
public @ResponseBody String saveSubscription(@RequestBody Subscription subscription) {
....
}
我的UI有Backbone代码就像,
var Subscription = Backbone.Model.extend({
urlRoot :http://localhost:8087/SpringRest/test',
});
$(document).ready(function() {
$('#new-subscription').click(function(ev) {
var subscription = new Subscription({
name : $('#dropdown').val(),
type : $('input[name=type]:checked').val(),
format : $('input[name=format]:checked').val(),
});
subscription.save();
});
通过使用此代码,我调用了Spring REST服务。这里Backbone将订阅数据发布为JSON。
但我希望将其发布为XML,然后在点击服务时弹出解组。
在从客户端点击服务之前,我如何解析Backbone模型JSON到XML?
答案 0 :(得分:2)
您可以通过覆盖sync
方法来修改Backbone如何同步数据。例如,模型定义可能看起来像
var Subscription = Backbone.Model.extend({
urlRoot: 'http://localhost:8087/SpringRest/test',
sync: function(method, model, options) {
if ((method !== "create") && (method !== "update"))
return Backbone.sync.apply(this, arguments);
options = options || {};
// what the server responds with
options.dataType = 'xml';
// the content type of your data
options.contentType = 'application/xml';
// what you send, your XML
// you will have to tailor it to what your server expects
var doc = document.implementation.createDocument(null, "data", null);
_.each(this.toJSON(), function(v, k) {
var node = doc.createElement(k);
var text = doc.createTextNode(v);
node.appendChild(text);
doc.documentElement.appendChild(node);
});
options.data = doc;
return Backbone.sync.call(this, method, model, options);
}
});
那会发送
<data>
<name>...</name>
<type>...</type>
<format>...</format>
</data>