Question

我创建了一个空白的MVC5控制器，我被告知要做，在创建带有多路连接子句的select语句后，我尝试将所选信息传递给视图，但在加载视图时，它会因此错误而崩溃： “传递到字典中的模型项的类型为'System.Collections.Generic.List 1[<>f__AnonymousType6 5 [System.DateTime，System.TimeSpan，System.String，System.Int32，System.String]]'，但是这个字典需要一个类型为'System.Collections.Generic.IEnumerable`1 [snBusService04.Models.trip]'的模型项。“

这是我的索引视图代码

 public ActionResult Index(string busRouteCode)
        {
            var tripInfo = "";

            if (busRouteCode != null)
            {
                HttpCookie busRouteCodeCookie = new HttpCookie("busRouteCodeCookie");
                busRouteCodeCookie.Value = busRouteCode;
                busRouteCodeCookie.Expires = DateTime.Now.AddHours(1);
                Response.Cookies.Add(busRouteCodeCookie);
            }
            else if (Request.Cookies["busRouteCodeCookie"] != null )
            {
                tripInfo = Request.Cookies["busRouteCodeCookie"].Value;
            }
            else
            {
                TempData["message"] = "Please select a bus route";
               return RedirectToAction("Index", "snBusRoutes");
            }

            var tripQuery = from br in db.busRoutes
                            join rs in db.routeSchedules on br.busRouteCode equals rs.busRouteCode
                            join t in db.trips on rs.routeScheduleId equals t.routeScheduleId
                            join d in db.drivers on t.driverId equals d.driverId
                            join b in db.buses on t.busId equals b.busId
                           // where br.busRouteCode == busRouteCode
                            select new
                            {
                                t.tripDate,
                                rs.startTime,
                                d.fullName,
                                b.busNumber,
                                t.comments
                            };
            var queryResult = tripQuery.AsEnumerable()
                                .Select(t => new
                                {
                                    t.tripDate,
                                    t.startTime,
                                    t.fullName,
                                    t.busNumber,
                                    t.comments
                                });

             return View(queryResult.ToList());            
        }

视图代码如下：

@model IEnumerable<snBusService04.Models.trip>

    @{
        ViewBag.Title = "Monitored Trip Information for " + Request.Cookies["busRouteCodeCookie"].Value;
    }

    <h2>@ViewBag.Title</h2>
    <h3>@TempData["message"]</h3>

<p>
    @Html.ActionLink("Create New", "Create")
</p>
<table class="table">
    <tr>
        <th>
            @Html.DisplayNameFor(model => model.tripDate)
        </th>
        <th>
            @Html.DisplayNameFor(model => model.startTime)
        </th>    
        <th>
            @Html.DisplayNameFor(model => model.fullName)
        </th>
        <th>
            @Html.DisplayNameFor(model => model.busNumber)
        </th>       
        <th>
            @Html.DisplayNameFor(model => model.comments)
        </th>   
    </tr>

    @foreach (var item in Model) {
        <tr>
            <td>
                @Html.DisplayFor(modelItem => item.tripDate)
            </td>
            <td>
                @Html.DisplayFor(modelItem => item.startTime)
            </td>  
            <td>
                @Html.DisplayFor(modelItem => item.fullName)
            </td>           
            <td>
                @Html.DisplayFor(modelItem => item.busNumber)
            </td>            
            <td>
                @Html.DisplayFor(modelItem => item.comments)
            </td>       
        </tr>
    }
</table>

Answer 1

您的观点期待IEnumerable<snBusService04.Models.trip>

将查询结果更改为以下命令，而不是匿名IEnumerable。（假设您的字段与您的命名结构相符）：

var queryResult = tripQuery.AsEnumerable()
             .Select(t => new snBusService04.Models.trip
             {
                 tripDate = t.tripDate,
                 startTime = t.startTime,
                 fullName = t.fullName,
                 busNumber = t.busNumber,
                 comments = t.comments
              });

显示所选信息的mvc5 linq错误

1 个答案: