使用get_form_kwargs时__init __（）得到了一个意外的关键字参数

Question

作为表单向导的一部分我尝试将表单向导中的get_form_kwargs方法中的参数传递给我的表单，然后传递给modelformset。我已经查看了很多关于SO的示例（例如here，here和here）

代码看起来不错（初学者），但它仍然会产生此错误：

异常类型：TypeError
异常值：__ init __（）得到了一个意外的关键字参数＆＃39; parent＆＃39;

相关views.py提取：

def get_form_kwargs(self, step=None):
        kwargs = {}
        if self.steps.current == 'assign_child':
            kwargs = super(checkout, self).get_form_kwargs(step)
            kwargs.update({
                'parent': self.request.user,
                })
            return kwargs

forms.py extract：

class bindBookingItems(ModelForm):
    class Meta:
        model = BookingItem
        fields = ('assignedKids',)
        widgets = {
                    'assignedKids': Select(attrs={'class': 'form-control',}),
            }
    def __init__(self, *args, **kwargs):
        parent = kwargs.pop('parent', None)
        super(bindBookingItems, self).__init__(*args, **kwargs)
        form.fields['assignedKids'].queryset = getChildren(parent.id)

checkout_bindBookingItemsFormSet = modelformset_factory(
        BookingItem, 
        form = bindBookingItems, 
        fields=('assignedKids', ),
        extra=0, max_num=5, can_delete=False)

我目前的想法是问题出在forms.py中。由于它的抱怨，这个论点显然正在被提起。但是，我想我会在超级声明之前正确地弹出kwarg。

我做错了什么？

更新了问题，其中包含混合中的模型形式。请忽略此信息。完全放下了我的想法。

使用追溯更新：

Traceback:
File "D:\Python27\Lib\site-packages\django\core\handlers\base.py" in get_response
  111.                     response = wrapped_callback(request, *callback_args, **callback_kwargs)
File "D:\Python27\Lib\site-packages\django\views\generic\base.py" in view
  69.             return self.dispatch(request, *args, **kwargs)
File "D:\Python27\Lib\site-packages\django\contrib\formtools\wizard\views.py" in dispatch
  237.         response = super(WizardView, self).dispatch(request, *args, **kwargs)
File "D:\Python27\Lib\site-packages\django\views\generic\base.py" in dispatch
  87.         return handler(request, *args, **kwargs)
File "D:\Python27\Lib\site-packages\django\contrib\formtools\wizard\views.py" in get
  255.         return self.render(self.get_form())
File "D:\Python27\Lib\site-packages\django\contrib\formtools\wizard\views.py" in get_form
  419.         return form_class(**kwargs)
File "D:\Python27\Lib\site-packages\django\forms\models.py" in __init__
  558.         super(BaseModelFormSet, self).__init__(**defaults)

Exception Type: TypeError at /checkout/
Exception Value: __init__() got an unexpected keyword argument 'parent'

Answer 1

以下是brilliant example，说明了如何正确覆盖get_form_kwargs。

我很困惑，因为我在S.O.找不到一个血统的例子。到目前为止。

假设这种形式：

from django import forms

from .models import MyModel


class MyForm(forms.ModelForm):

    class Meta:
        model = MyModel

    def __init__(self, user_id, *args, **kwargs):
        super(MyForm, self).__init__(*args, **kwargs)

        # set the user_id as an attribute of the form
        self.user_id = user_id

现在已经定义了表单，视图需要使用用户id注入表单：

from django.views.generic import UpdateView

# this assumes that django-braces is installed
from braces.views import LoginRequiredMixin

from .forms import MyForm
from .models import MyModel


class MyUpdateView(LoginRequiredMixin, UpdateView):
    model = MyModel
    form_class = MyForm
    success_url = "/someplace/"

    def get_form_kwargs(self):
        """This method is what injects forms with their keyword
            arguments."""
        # grab the current set of form #kwargs
        kwargs = super(MyUpdateView, self).get_form_kwargs()
        # Update the kwargs with the user_id
        kwargs['user_id'] = self.request.user.pk
        return kwargs