Question

在致电GPPSignIn之前，有没有办法向[self.signIn authenticate];对象提供用户电子邮件，以便用户无需在浏览器/ Google Plus应用中输入该网址即可使用Google帐户登录？我想将用户电子邮件传递给登录表单，以便用户只需输入密码即可。我之前要求用户提供电子邮件，因此在大多数情况下我可以使用它来帮助他以更少的步骤登录。 self.signIn.userEmail是只读的，所以对我没什么帮助。

Answer 1

如果第一次不需要，用户需要输入电子邮件和密码。

- (IBAction)Btn_gogleShare:(id)sender {

            if ([[GPPSignIn sharedInstance] authentication]) {
                NSLog(@"share");
                [self GoogleShare];
            } else {
                NSLog(@"Login");
                [self GoogleLogin];

            }
     }

#pragma mark - Google+所有活动

#pragma mark - Google+ Login

- (void)GoogleLogin{

    GPPSignIn *signIn = [GPPSignIn sharedInstance];
    signIn.shouldFetchGooglePlusUser = YES;
    signIn.shouldFetchGoogleUserEmail = YES;  // Uncomment to get the user's email

    // You previously set kClientId in the "Initialize the Google+ client" step
    signIn.clientID = kClientID;
    signIn.scopes = @[ kGTLAuthScopePlusLogin ];
    //signIn.scopes = @[ @"profile" ];            // "profile" scope

    // Optional: declare signIn.actions, see "app activities"
    signIn.delegate = self;

    [signIn authenticate];

    [self showLoadingView:@"Authorizing..."];

}

- (void)finishedWithAuth: (GTMOAuth2Authentication *)auth
                   error: (NSError *) error {
    NSLog(@"Received error %@ and auth object %@",error, auth);
    //  NSLog(@"%@", signIn.authentication.userEmail);
    [self hideLoadingView];

    [self GoogleShare];
}

#pragma mark - Google+ share

- (void)GoogleShare{

    id<GPPNativeShareBuilder> shareBuilder = [[GPPShare sharedInstance] nativeShareDialog];

    // This line will fill out the title, description, and thumbnail from
    // the URL that you are sharing and includes a link to that URL.
    [shareBuilder setURLToShare:[NSURL URLWithString:@"https://www.example.com/restaurant/sf/1234567/"]];

    [shareBuilder open];

}


#pragma mark - Google+ signOut

- (void)signOut {
    [[GPPSignIn sharedInstance] signOut];
}

Google Plus登录 - 提供用户电子邮件重定向到浏览器/ Google Plus应用

1 个答案: