如何解决错误：操作无法完成。 （可可错误3840.）json iOS？

Question

我编写了GET方法代码以从服务器（json格式）检索详细信息。但是我收到错误（操作无法完成）。 谁能请我提供一些有关此事的信息？ 我的代码：

-(void)getResponseWithOutBodywithMethod:(NSString*)method
{
NSMutableURLRequest *request =
[NSMutableURLRequest requestWithURL:url];
[request setHTTPMethod:method];

//[request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
// [request setTimeoutInterval:20.0];
 NSURLConnection *conn=[[NSURLConnection alloc]initWithRequest:request delegate:self];
if (conn)
{
    receivedData = [[NSMutableData alloc] init] ;
}
}
#pragma mark NSURLConnection delegate methods
- (void) connection:(NSURLConnection *)connection didReceiveResponse:  (NSURLResponse *)response{
/* This method is called when the server has determined that it has
 enough information to create the NSURLResponse. It can be called
 multiple times, for example in the case of a redirect, so each time
 we reset the data. */
[receivedData setLength:0];
}
- (void) connection:(NSURLConnection *)connection didReceiveData:  (    NSData *)data{
[receivedData appendData:data];
 }
 - (void) connection:(NSURLConnection *)connection didFailWithError:(  NSError *)error{
completion(nil, error);
NSLog(@"%@",[error localizedDescription]);

  }
    - (void) connectionDidFinishLoading:(NSURLConnection *)connection{

if (receivedData != nil) {
    NSError *jsonParsingError = nil;
    NSMutableDictionary *dict = [NSJSONSerialization JSONObjectWithData:receivedData
                                                         options:kNilOptions error:&jsonParsingError];

    NSString* str = [[NSString alloc] initWithData:receivedData encoding:NSUTF8StringEncoding];
    NSLog(@"error %@",jsonParsingError.localizedDescription);
    UIAlertView *alertView = [[UIAlertView alloc] initWithTitle:@"ER" message:str delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil, nil];
    [alertView show];
    if (dict == nil && [dict count]==0) {

             UIAlertView *alertView = [[UIAlertView alloc] initWithTitle:@"Error" message:jsonParsingError.localizedDescription delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil, nil];
            [alertView show];
         completion(nil, jsonParsingError);
    }
    else {

        completion(dict, nil);



    }
}
else {
    completion(nil, [NSError errorWithDomain:@"http" code:-1 userInfo:nil]); //todo proper error
    UIAlertView *alertView = [[UIAlertView alloc] initWithTitle:@"Error" message:@"Failed to get data." delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil, nil];
    [alertView show];
}
}

Answer 1

好吧，我认为你的Json就是问题所在。

如果您的服务器正在响应：

东西= somethingelse

这不是正确的格式。您需要对Json进行编码，使其看起来像：

[{“key”：“value”，“key”：“value”}]