我必须在弹出窗口中显示用户登录页面,并且必须使用角度js通过服务器验证用户名和密码。我创建了一个app模型文件,一个控制器,服务和一个指令。我的代码看起来像吼叫,
app.js
angular.module('mint', ['ngAnimate', 'toastr']);
mycontroller.js
angular.module('mint').controller(
'headercontroller',
[
'$scope',
'headerservice',
'toastr',
function($scope, headerservice, toastr) {
$scope.showModal = false;
$scope.toggleModal = function() {
$scope.showModal = !$scope.showModal;
};
$scope.userSignin = function(){
$scope.userloginbtn = false;
if($scope.signin_form.$valid){ //Error on this line signin_form is undefine. using $valid for undefine
var record = {};
angular.extend(record, $scope.signinForm);
console.log(record);
}else {
$scope.signin_form.submitted = false;
$scope.userloginbtn = true;
}
};
} ]);
我的directive.js文件是
angular
.module('mint')
.directive(
'modal',
function() {
return {
template : '<div class="modal fade">'
+ '<div class="modal-dialog">'
+ '<div class="modal-content">'
+ '<div class="modal-header">'
+ '<button type="button" class="close" data-dismiss="modal" aria-hidden="true">×</button>'
+ '<h4 class="modal-title"><span><i class="fa fa-user"></i> {{ title }}</span></h4>'
+ '</div>'
+ '<div class="modal-body" ng-transclude></div>'
+ '</div>' + '</div>' + '</div>',
restrict : 'E',
transclude : true,
replace : true,
scope : true,
link : function postLink(scope, element, attrs) {
scope.title = attrs.title;
scope.$watch(attrs.visible, function(value) {
if (value == true)
$(element).modal('show');
else
$(element).modal('hide');
});
$(element).on('shown.bs.modal', function() {
scope.$apply(function() {
scope.$parent[attrs.visible] = true;
});
});
$(element).on('hidden.bs.modal', function() {
scope.$apply(function() {
scope.$parent[attrs.visible] = false;
});
});
}
};
});
我的html文件看起来像
<!DOCTYPE html>
<html lang="en" ng-app="mintmygold">
<body>
<div class="container-fluid ban_bg"
ng-controller="headercontroller">
<div class="but_bg">
<button type="button" class="btn btn-default btn_sin" ng-click="toggleModal()">
<span><i class="fa fa-key"></i> Sign In</span>
</button>
</div>
<modal title="Login" visible="showModal">
<form role="form" name="signin_form" class="signup_form" novalidate
ng-model="signin_form">
<div class="form-group">
<p class="infoMsg" ng-model="signinform_info">Please fill in your login credentials:</p>
</div>
<div class="form-group">
<label for="email">Email address</label>
<input ng-model="signinForm.userEmail" name="userEmail" type="email" class="form-control" id="email" placeholder="Enter email" required />
<div
ng-show="signin_form.$submitted || signin_form.userEmail.$touched">
<span ng-show="signin_form.userEmail.$error.required">Enter your
email.</span> <span ng-show="signin_form.userEmail.$error.email">This
is not a valid email.</span>
</div>
</div>
<div class="form-group">
<label for="password">Password</label>
<input ng-model="signinForm.userPassword" name="userPassword" type="password" class="form-control" id="password" placeholder="Password" required />
<div
ng-show="signin_form.$submitted || signin_form.userPassword.$touched">
<span ng-show="signin_form.userPassword.$error.required">Enter your
password.</span>
</div>
</div>
<button ng-disabled="signin_form.$invalid || !userloginbtn" ng-model="signin" ng-click="userSignin()" type="submit" class="btn btn-primary">Submit</button>
</form>
</modal>
</div></body></html>
现在我可以在点击登录按钮时显示弹出窗口。当我提交表单时,我无法从控制器中的弹出窗口中获取电子邮件和密码值的值。我使用示波器的错误是什么?请任何人帮助我。
答案 0 :(得分:1)
快速忽略,这似乎是一个愚蠢的错误。改变你的行
这
angular.module('mint', ['ngAnimate', 'toastr']);
要
angular.module('mintmygold', ['ngAnimate', 'toastr']);
答案 1 :(得分:0)
您正在使用scope:true表示您的指令正在创建子范围并从其父级继承属性。 因此,在控制器范围内不存在您在指令范围中定义的任何属性。
更改表单名称= signin_form 对于表单名称= $ parent.signin_form或scope:false应解决问题
我没有测试过这个。而且这不是一个好的解决方案。 我可能会创建一个服务来启动弹出窗口并返回一个相应的解析/拒绝的承诺。
app.js
var app = angular.module('plunker', []);
app.controller('MainCtrl', function($scope, modal) {
$scope.launch = function(){
modal.show().then(function(user){
console.log(user)
}, function(err){
console.log(err)
});
}
});
app.factory('modal', ["$document", "$compile", "$rootScope", "$templateCache", "$timeout", "$q",
function ($document, $compile, $rootScope, $templateCache, $timeout, $q) {
var $body = $document.find('body');
return {
show: function(){
var defer = $q.defer(),
child = $rootScope.$new();
child.user = {};
child.close = function(){
defer.reject('canceled');
tpl.remove();
}
child.submit = function(){
defer.resolve(child.user);
tpl.remove();
}
var tpl = angular.element($templateCache.get('modal.html'));
$compile(tpl)(child);
$body.append(tpl);
return defer.promise;
}
};
}]);
的index.html
<script type="text/ng-template" id="modal.html">
<div class="modal in" style="position: static; display: block">
<div class="modal-dialog">
<form ng-submit="submit()" class="modal-content">
<div class="modal-header">
<button type="button" class="close" ng-click="close()" aria-label="Close"><span aria-hidden="true">×</span></button>
<h4 class="modal-title">Modal title</h4>
</div>
<div class="modal-body">
Email: <input ng-model="user.email"></input><br>
Password: <input ng-model="user.password"></input>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-default" ng-click="close()">Close</button>
<button type="submit" class="btn btn-primary">Sign in</button>
</div>
</form>
</div>
</div>
</script>
<button type="button" ng-click="launch()" class="btn btn-primary">Show modal</button>
这只是一个概念证明。我认为足以让你入门。我强烈建议您查看UI Bootstrap以及实施模式的方式