我终于想出了如何制作我正在寻找的功能,但是我遇到的问题是我想让它只重复询问密码输入,而不是用户名和密码。
#include "stdafx.h"
#include <iostream> // library that contains basic input output functions
#include <string> // library for c++ strings
using namespace std;
int main()
{
//Username and Password to validate credentials
const string USERNAME = "myself";
const string PASSWORD = "stanley";
const string USERNAME2 = "otherperson";
const string PASSWORD2 = "otherpassword";
//strings in which user will enter username and password
string username, password;
int passattempts = 0;
do{
// Prompting user to input username
cout << "Enter Username : ";
cin >> username;
//Checking if username length is less than 4 characters then display an error message
if (username.length() < 4)
{
cout << "Username length must be atleast 4 characters long.";
}
else //if username length is greater than 3
{
//promprting user for password
cout << "Enter Password : ";
cin >> password;
//Checking if password length is less than 6 characters then display an error message
if (password.length() < 6)
{
cout << "Password length must be atleast 6 characters long.";
}
else //if password length is greater than 5
{
//Checking if user's entered credentials are equal to actual USERNAME and PASSWORD
if (username == USERNAME && password == PASSWORD || username == USERNAME2 && password == PASSWORD2)
{
cout << "User credentials are correct!!!" << endl;
break;
}
else
{
cout << "Invalid login details" << endl;
++passattempts;
}
}
}
} while (passattempts != 3);
system("pause");
return (0);
}
答案 0 :(得分:2)
然后在密码do循环之外输入(并检查)用户名。
如果您希望允许用户重新输入太短的用户名,您可以随时将这些内容置于另一个do循环中。没有规则说你只允许一个循环:)
类似(伪代码)
do
{
prompt for username
read username
} while (username invalid)
do
{
prompt for password
read password
} while (password invalid)
关于你是否告诉用户为什么他们的数据无效,还有一个哲学论点。我没有被吸引,安全人员可以得到一点...... 激烈。