使用Android应用程序我将纬度和经度值发送到数据库 这是我的数据库
现在在网页中我需要显示 K.Prathibha.N
所走的总距离我使用 Google Maps Direction API 来查找距离,但它接受'id = 2'作为来源,'id = 5'作为目的地。 但我的座右铭是找到行进的总距离,即id_2到id_3到id_4到id_5。
我在这里使用while循环。
代码段:
<?php
$params_string="";
$pname = $_POST['name']; //name is passed from a dropdown
$query = "SELECT * FROM information WHERE mobile=? ORDER BY id DESC ";
$result = $dbConnection->prepare($query);
$result->execute(array($pname));
if($result->rowCount() >0)
{
$params = array();
while($row = $result->fetch())
{
$mobile = $row['mobile'];
$latitude = $row['latitude'];
$cname = $row['name'];
$longitude = $row['longitude'];
$lat = "17.4136846";
$long = "78.49228289999996";
$params = array("origin" => $latitude.",".$longitude,"destination" => $lat.",".$long,"sensor" => 'true',"units" => 'imperial');
//Join parameters into URL string
foreach($params as $var => $val)
{
$params_string .= '&' . $var . '=' . urlencode($val);
}
}
}
// Request URL
$url = "http://maps.googleapis.com/maps/api/directions/json?".ltrim($params_string, '&');
// Make our API request
$curl = curl_init();
curl_setopt($curl, CURLOPT_URL, $url);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1);
$return = curl_exec($curl);
curl_close($curl);
// Parse the JSON response
$directions = json_decode($return);
// Show the total distance
print('<p><strong>Total distance:</strong> ' . ceil(($directions->routes[0]->legs[0]->distance->text)* 1.609344) .' KM'. '</p>');
?>
现在,如何在此处传递目标值。
我的任务是将数据库值传递给变量lat和long ....例如,我已经传递了手动值...如何同时获取数据库值,以便origin获取id 2并且destination获取id 3值
示例 - 如果它正在接受
原点为id-2,然后目的地应为id-3 next
原点为id-3,然后目的地应为id-4,依此类推
最后根据可用的地理位置给出特定日期的总行程距离。
在3天以上的时间里挣扎。
任何建议都会有很大的帮助。
答案 0 :(得分:0)
您可以在while循环中连续使用调用此函数
$latitude = $row['latitude'];
$longitude = $row['longitude'];
$lat = "17.4136846";
$long = "78.49228289999996";
$distance=distance($latitude,$longitude,$lat,$long,"k");
and the function is
function distance($lat1, $lon1, $lat2, $lon2, $unit)
{
$theta = $lon1 - $lon2;
$dist = sin(deg2rad($lat1)) * sin(deg2rad($lat2)) + cos(deg2rad($lat1)) * cos(deg2rad($lat2)) * cos(deg2rad($theta));
$dist = acos($dist);
$dist = rad2deg($dist);
$miles = $dist * 60 * 1.1515;
$unit = strtoupper($unit);
if ($unit == "K") {
return ($miles * 1.60934);
} else if ($unit == "N") {
return ($miles * 0.8684);
} else {
return $miles;
}
}
//remember you pass last parameter in function k. so it you you the //distance in kilometer
答案 1 :(得分:0)
嗯,你可以这样做。
例如
$qry = mysql_query("select * from store");
$num = mysql_num_rows($qry);
while($row = mysql_fetch_array($qry)){
$lat[] = $row['lat'];
$long[] =$long['long'];
}
for($i=0;$i<$num;$i++){
$distance=distance($lat[$i],$long[$i],$lat[$i+1],$long[$i+1],"k");
}
function:
function distance($lat1, $lon1, $lat2, $lon2, $unit)
{
$theta = $lon1 - $lon2;
$dist = sin(deg2rad($lat1)) * sin(deg2rad($lat2)) + cos(deg2rad($lat1)) * cos(deg2rad($lat2)) * cos(deg2rad($theta));
$dist = acos($dist);
$dist = rad2deg($dist);
$miles = $dist * 60 * 1.1515;
$unit = strtoupper($unit);
if ($unit == "K") {
return ($miles * 1.60934);
} else if ($unit == "N") {
return ($miles * 0.8684);
} else {
return $miles;