Question

正如您在打击代码中看到的，我想将自定义xml反序列化为对象，我不知道有多少代码属性，所以我想过滤包含“代码”的所有属性，并将其映射到List属性。有没有办法实现这个功能？

<Root>
     <FirstElement FirstCode="1" SecondCode="2" ThirdCode="3" Id="1" Name="Element" />
</Root>

public class MappedClass
{
   [XmlAttribute(AttributeName = "Name")]
   public string Name {get;set;}

   [XmlAttribute(AttributeName = "Id")]
   public int Id {get;set;}

   [?]
   public List<Code> Codes {get;set;}

}

public Class Code
{
   public string Name {get;set;}

   public string Value {get;set;}
}

Answer 1

我想你可以。使用UnknownAttribute事件将未知属性放入代码集合：

        var serializer = new XmlSerializer(typeof(MappedClass));
        serializer.UnknownAttribute += 
            (s, e) =>
            {
                (e.ObjectBeingDeserialized as MappedClass).Codes.Add(new Code { Name = e.Attr.Name, Value = e.Attr.Value });                                        
            };

有没有办法用指定的关键字将xml反序列化为对象？

1 个答案: