重构xml文档

Question

这是我的xml文档结构，

<worldpatentdata>
    <patent-family>
        <exchange-documents>......</exchange-documents>
        <exchange-documents>......</exchange-documents>
        <exchange-documents>......</exchange-documents>
        <familymember>.....</familymember>
        <exchange-documents>......</exchange-documents>
        <exchange-documents>......</exchange-documents>
        <familymember>.....</familymember>
        <exchange-documents>......</exchange-documents>
        <exchange-documents>......</exchange-documents>
        <familymember>.....</familymember>
    </patent-family>
</worldpatentdata>

在上面的xml结构中，发现所有<exchange-documents>元素都是<patent-family>元素的子节点。 我希望这些<exchange-documents>元素作为<family-member>元素的子节点，以便xml具有以下结构，

<worldpatentdata>
    <patent-family>
        <familymember>.....
            <exchange-documents>......</exchange-documents>
            <exchange-documents>......</exchange-documents>
            <exchange-documents>......</exchange-documents>
        </familymember>
        <familymember>.....
            <exchange-documents>......</exchange-documents>
            <exchange-documents>......</exchange-documents>
        </familymember>
        <familymember>.....
            <exchange-documents>......</exchange-documents>
            <exchange-documents>......</exchange-documents>
        </familymember>
    </patent-family>
</worldpatentdata>

任何人都可以帮我吗？ 感谢

Answer 1

通过DOM迭代<patent-family>的孩子，记住你在途中遇到的每个<exchange-documents>。每当您看到<familymember>时，请移动其下的记忆元素。

Answer 2

在我的头顶上，一种方法可能是：

1. 使用XDocument加载xml，并创建一个tempXDocument。
2. foreach (XElement...通过元素并添加到<exchange-documents>
的XmlNodeList项
3. 找到<familymember>时，在tempXDocument中添加<familymember>;并将XmlNodeList添加到tempXDocument。
4. 保存tempXDocument。