Question

echo for /f "delims=" %%%i in ^(^'DIR /A -H /B^'^) do set "check^=^^!check^^!,"%%%i"" >> Uninstall.cmd

结果

for /f "delims=" %%i""

原始代码我试图回复到Uninstall.cmd

for /f "delims=" %%i in ('DIR /A -H /B') do set "check=!check!,"%%i""

任何人都可以帮我弄清楚如何让这行代码完全转义，以便将其输出到文件中吗？

Answer 1

如果您没有启用延迟扩展

echo for /f "delims=" %%%%i in ('DIR /A-H /B') do set "check=!check!,"%%%%i""

如果您启用了延迟扩展，则需要转义感叹号

echo for /f "delims=" %%%%i in ('DIR /A-H /B') do set "check=^!check^!,"%%%%i""

但是，如果代码在块内执行，则右括号也需要转义

if 1==1 (
    echo for /f "delims=" %%%%i in ('DIR /A-H /B'^) do set "check=!check!,"%%%%i""

    :: OR

    echo for /f "delims=" %%%%i in ('DIR /A-H /B'^) do set "check=^!check^!,"%%%%i""
)

如何成功回复For循环到批处理脚本？

1 个答案: