Question

这是我的代码，错误显示在标题中。在编译器中：

1>c:\users\ägaren\documents\visual studio 2010\projects\yt tutorial hd\yt tutorial hd\main.cpp(26): error C2446: '==' : no conversion from 'const char *' to 'int'

和

1>c:\users\ägaren\documents\visual studio 2010\projects\yt tutorial   hd\yt tutorial hd\main.cpp(26): error C2040: '==' : 'int' differs in levels of       indirection from 'const char [4]'

#include <iostream>
#include <windows.h>
#include <string> 
using namespace std;


int main()
{
   int gold=600, level=1, exp, damage=10, health=100, mana=100, manaLevel=1;          // Main Vars      
   string name;
   cout << "Hello, what is your name?: ";
   cin >> name; 
   cout << "Welcome " << name << " to the field of war,\nYou will stumble upon many other brave warriors.\nTake care and good luck.\n";
   Sleep(500);

   cout << "You're first task is to eliminate the Orc leader.\n";
   int orc=15, troll=25, mage=50; // Enemy Vars
   int healthpotion=25, manaPotion=25; // Potions vars
   int ifAttack; // if the user chooses to attack or not.
   Sleep(500);
   cout << "Tossan: " << name << " I hereby order you to attack the orc, he is up north.\nThis message will delete in 2.5 seconds.";
   Sleep(2500);
   system("cls"); // 1st screen clear.
   cout << "After heading north you stumble upon the Orc, will you attack him? [y/n]\n";
   cin >> ifAttack;
   if (ifAttack == "yes")

}

if（ifAttack ==“是”）是什么给了我错误，==有下划线但我无法找到如何解决它。 C ++

Answer 1

声明ifAttack不是int，而是像：

string ifAttack;

然后您就可以像以前一样阅读它：cin >> ifAttack;

但是，因为您只关心用户是否输入了“＆＃39;对于第一个字符，将if语句更改为：

if(ifAttack.front() == 'y' || ifAttack.front() == 'Y')

修改

过滤用户输入可能是一项艰巨的任务。但是，如果您决定要采用它，则可以比较整个 string而不仅仅是第一个字符。就这样＆＃34;黄色大象＆＃34;并不意味着＆＃34;是＆＃34;：

if(_stricmp(ifAttack.c_str(), "yes") || _stricmp(ifAttack.c_str(), "y"))

_stricmp是仅限Microsoft的功能：https://msdn.microsoft.com/en-us/library/k59z8dwe.aspx strcasecmp是Linux等价物：http://pubs.opengroup.org/onlinepubs/009695399/functions/strcasecmp.html

我建议您保存过滤输入，直到项目结束。这可能很乏味。例如，上面的字符串比较不匹配＆＃34;是！＆＃34;。

错误：操作数类型不兼容（＆＃34; int＆＃34;和＆＃34; const char *＆＃34;）c ++

1 个答案: