Question

连接GetWaypoints方法生成的列表的最佳方法是什么？我想连接JobWaypoints下的所有项目，并用新的行分隔它们。

我似乎无法找到直接访问我创建的JobWaypoints列表中waypoints项的最佳方法。

Window.cs

List<JobComponent.JobList> waypoints = JobComponent.GetWaypoints(jobId);

JobComponents.cs

    public static List<JobList> GetWaypoints(int jobId)
    {
        // Get destination
        const string query = "SELECT address FROM waypoint " +
                             "WHERE id NOT IN(" +
                             "(SELECT MIN(ID) FROM waypoint where booking_id=@id)," +
                             "(SELECT MAX(ID) FROM waypoint where booking_id=@id)) " +
                             "AND booking_id=@id";
        var jobList = new List<JobList>();
        using (var cmd = new MySqlCommand(query, DbObject.Connection))
        {
            if (DbObject.Connection.State != ConnectionState.Open)
            {
                DbObject.OpenConnection();
            }
            cmd.Parameters.AddWithValue(("@id"), jobId);
            try
            {
                using (MySqlDataReader dataReader = cmd.ExecuteReader())
                {
                    while (dataReader.Read())
                    {
                        var item = new JobList
                        {
                            JobWaypoints = dataReader["address"] + ""
                        };
                        jobList.Add(item);
                    }
                    dataReader.Close();
                    DbObject.CloseConnection();
                    return jobList;
                }
            }
            catch (Exception ex)
            {
                ErrorHandlingComponent.LogError(ex.ToString());
                throw;
            }
        }
    }

Answer 1

我使用了string.Join方法。以下示例将创建一个字符串，其中包含所有JobWaypoints值，并在每个值之间使用逗号（，）：

List<JobComponent.JobList> waypoints = JobComponent.GetWaypoints(jobId);
string s = string.Join(",", waypoints.Select(i => i.JobWaypoints));

连接生成列表中`JobDestination`下的所有项目

1 个答案: