Question

当我使用customerNumber的任何值运行它时，它总是返回if语句中的第一个警报消息。这有什么不对？

var customerNumbers = 13;
var winningNumbers = [];
winningNumbers.push(12, 17, 24, 37, 38, 43);
var match = false;
for (i=0; i<winningNumbers.length; i++) {
    if (winningNumbers[i] == customerNumbers) {
        match = true;
    }
}
if (match = true) {
    alert("This Week's Winning Numbers are:\n" + winningNumbers.toString() + 
    "\nThe Customer's Number is:\n" + customerNumbers + "\nWe have a match and a winner!");
}
else {
    alert("This Week's Winning Numbers are:\n" + winningNumbers.toString() + 
    "\nThe Customer's Number is:\n" + customerNumbers + "\nSorry, you are not a winner this week.");
}

Answer 1

您没有将您要分配match的布尔true与true与布尔值match进行比较。你需要使用double或triple =。

match = true // Sets match to true
match == true // Compares match to true
match === true // Strictly compares match to true

所以添加更多相同的标志，它应该有用。

Answer 2

请勿在if语句中使用赋值运算符（=）。使用相等运算符（===）。

if (match === true)

JavaScript：为什么boolean总是返回true

2 个答案: